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iosswiftnsurl
Alex Beals
Alex Beals

Reputation: 2135

How To Get HTML source from URL with Swift

I need to look at the HTML of a page given by a certain URL. If I have this, what is the most efficient and synchronous way to get the HTML source for that URL using Swift? I haven't been able to find a concise way online that returns it into a variable as opposed to printing it in a completionHandler.

I need to manipulate the source outside of whatever call uses the URL. How is this done in Swift?

Upvotes: 32

Views: 57290

Answers (5)

ha100
ha100

Reputation: 1592

more compact functional example

let myURLString = "https://google.com"

let myHTMLString = try URL(string: myURLString)
    .flatMap { try Data(contentsOf: $0) }
    .flatMap { String(data: $0, encoding: .ascii) }

Upvotes: 6

DCMaxxx
DCMaxxx

Reputation: 2574

Disclaimer : Since this is getting quite a lot of views, I just want to remind everyone that this answer here is synchronous, and will block your app if you do it on the main thread. You should always do this asynchronously (in a background thread), but the question asked for a synchronous method, so it would be out of scope to explain how to do it here.

You should probably look at the method :

+ stringWithContentsOfURL:encoding:error (docs)

You would call it like this in Objective C :

NSString *myURLString = @"http://google.com";
NSURL *myURL = [NSURL URLWithString:myURLString];

NSError *error = nil;
NSString *myHTMLString = [NSString stringWithContentsOfURL:myURL encoding: NSUTF8StringEncoding error:&error];

if (error != nil)
{
    NSLog(@"Error : %@", error);
}
else
{
    NSLog(@"HTML : %@", myHTMLString);
}

So in Swift 3 and 4, the equivalent would be :

let myURLString = "https://google.com"
guard let myURL = URL(string: myURLString) else {
    print("Error: \(myURLString) doesn't seem to be a valid URL")
    return
}

do {
    let myHTMLString = try String(contentsOf: myURL, encoding: .ascii)
    print("HTML : \(myHTMLString)")
} catch let error {
    print("Error: \(error)")
}

You might want to adapt the encoding (see the constants) depending on which encoding your page's using.

Old answer, Swift 2.2 :

let myURLString = "http://google.com"
guard let myURL = NSURL(string: myURLString) else {
    print("Error: \(myURLString) doesn't seem to be a valid URL")
    return
}

do {
    let myHTMLString = try String(contentsOfURL: myURL)
    print("HTML : \(myHTMLString)")
} catch let error as NSError {
    print("Error: \(error)")
}

Old answer, Swift 1.2 :

let myURLString = "http://google.com"

if let myURL = NSURL(string: myURLString) {
    var error: NSError?
    let myHTMLString = NSString(contentsOfURL: myURL, encoding: NSUTF8StringEncoding, error: &error)

    if let error = error {
        println("Error : \(error)")
    } else {
        println("HTML : \(myHTMLString)")
    }
} else {
    println("Error: \(myURLString) doesn't seem to be a valid URL")
}

Upvotes: 59

Crashalot
Crashalot

Reputation: 34513

Swift 3:

    if let url = URL(string: "https://www.google.com/trends/hottrends/atom/hourly") {
        do {
            let contents = try String(contentsOf: url)
            print(contents)
        } catch {
            // contents could not be loaded
        }
    } else {
        // the URL was bad!
    }

Upvotes: 8

Javier Cadiz
Javier Cadiz

Reputation: 12536

This is the way to go in Swift 2:

let myURLString = "https://duckduckgo.com/"

if let myURL = NSURL(string: myURLString) {

    do {
        let myHTMLString = try String(contentsOfURL: myURL, encoding: NSUTF8StringEncoding)
        print("HTML : \(myHTMLString)")
    } catch {
        print("Error : \(error)")
    }
} else {
    print("Error: \(myURLString) doesn't  URL")
}

Also as an extra related to previous answers:
Note that Swift 2 introduces a new error handling approach that produces much clearer code for programmers to read, it does away with complexities like & to pass in NSErrors, and it gives you greater safety by ensuring you catch all errors.

Only use try! if you are 100% sure that the call won't fail.

Further reading: https://www.hackingwithswift.com/new-syntax-swift-2-error-handling-try-catch

Upvotes: 4

Meseery
Meseery

Reputation: 1855

An updated @DCMaxx answer to Swift 2.2 :

let myURLString = "http://www.yahoo.com"

if let myURL = NSURL(string: myURLString) {
    var error: NSError?
    let myHTMLString = try! NSString(contentsOfURL: myURL, encoding: NSUTF8StringEncoding)

    if let error = error {
        print("Error : \(error)")
    } else {
        print("HTML : \(myHTMLString)")
    }
} else {
    print("Error: \(myURLString) doesn't  URL")
}

Upvotes: 6

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