CODEWITHSUNDEEP
c++
DLunin
DLunin

Reputation: 1070

C++ compile-time type comparsion

Consider the function foo. 

template <typename T>
void foo() {
    do_something();
    if (T == int) {
        do_somehting_else();
    }
}

In other words, I want it to do_something() and then, if the type is int, do_something_else()

Of course if (T == int) { won't compile. Still: is there any way to compare types in compile-time in C++?

Upvotes: 2

Views: 134

Answers (2)

Basile Starynkevitch
Basile Starynkevitch

Reputation: 1

Just use a template specialization.

template <typename T> void foo() { do_something(); }

template<> void foo<int>() { do_something(); do_something_else(); };

Upvotes: 5

Daniel Frey
Daniel Frey

Reputation: 56921

You can use

#include <type_traits>

// ...

template <typename T>
void foo() {
    do_something();
    if (std::is_same<T,int>::value) {
        do_somehting_else();
    }
}

You can learn more about type traits here.

Upvotes: 5

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