CODEWITHSUNDEEP
php
Nickool
Nickool

Reputation: 3702

print function and parenthesis what is happening?

surprisingly these are different and I cannot understand what is going on:

var_dump(print'2');
echo "<br>";
var_dump((print '2')+3);
echo "<br>";
var_dump(print '2'+3);
echo "<br>";
echo '1'.(print '2')+3;

here is the output:

2int(1) 
2int(4) 
5int(1) 
214

I know that print function outputs a string and this string is a number so it it showing me an integer as a value but I don't exactly understand what's happening here would someone please explain it? why +3 doesn't affect in line 2? why the vardump amount is different?

Upvotes: 0

Views: 55

Answers (3)

Mark Baker
Mark Baker

Reputation: 212442

For line #1

print '2'

prints 2 and returns a 1 value that is then var_dumped() as int(1)

For line #2

print '2'

prints 2 and returns a 1 value that is then added to 3 before being var_dumped() as int(4)

For line #3

print '2'+3

prints 5 (the sum of 2 and 3) and returns a 1 value that is then var_dumped() as int(1)

for line #4

(print '2')

prints 2 and returns a 1 which is added to 3 giving 4; the echo then outputs 1 followed the result of that sum (4)

Upvotes: 0

Mithun Satheesh
Mithun Satheesh

Reputation: 27855

Refer the php docs for print

Print outputs the argument passed to it and always returns 1.

So below outputs are

var_dump(print'2'); 
// outputs two and gives int 1 to vardump
var_dump((print '2')+3);
// outputs 2 and adds 3 to retuned 1 to pass 4 to vardump
var_dump(print '2'+3);
//prints 2+3=5 and gives 1 to var_dump
echo '1'.(print '2')+3; 
// prints 2 first then 1 is concatinated with 4 which is sum of 3 and 1 from print

Upvotes: 1

Sam
Sam

Reputation: 20486

According to the documentation, print:

Returns 1, always.

To your examples:

  • var_dump(print'2'); will print the string 2 and return/dump the integer 1.
  • var_dump((print '2')+3); will print the string 2 and return/dump the integer 1 + 3.
  • var_dump(print '2'+3); will print '2' + 3, which evaluates to 5, and then return/dump the integer 1.
  • echo '1'.(print '2')+3; will print 2 and then echo 1 concatenated with sum of 1, from print '2', and 3.

Upvotes: 1

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