Reputation: 3009
Question from a networking class:
"In a csma/cd lan of 2 km running at 100 megabits per second, what would be the minimum frame size to hear all collisions?"
Looked all over and can't find info anywhere on how to do this. Is there a formula for this problem? Thanks for any help.
Upvotes: 11
Views: 22974
Reputation:
bandwidth delay product is the amount of data on transit. propagation delay is the amount of time it takes for the signal to propagate over network.
propagation delay=(lenght of wire/speed of signal). assuming copper wire i.e speed =2/3* speed of light
propagation delay =(2000/(2*3*10^8/3)) =10us
round trip time is the time taken for message to travel from sender to receiver and back from receiver to sender.
round trip time =2*propagation delay =20us
minimum frame size =bandwidth *delay (rtt)
frame size = bandwidth *rtt =100Mbps*20us=2000bits
Upvotes: 21