CODEWITHSUNDEEP
cmalloc
Greg Brinker
Greg Brinker

Reputation: 59

Malloc allocating same address in memory?

I found similar questions to mine, but I still can't figure out why my code is acting the way it is.

I have a struct called "rectangle", and here is the code that I am trying to run:

Rectangle *newRect = (Rectangle *)malloc(sizeof(Rectangle));
Rectangle *newRect2 = (Rectangle *)malloc(sizeof(Rectangle));
printf("rect1: %p rect2: %p",newRect,newRect2);

It outputs the same address for both of them, what am I doing wrong?

Thanks!

Upvotes: 2

Views: 2026

Answers (1)

Jens Gustedt
Jens Gustedt

Reputation: 78963

You probably don't compile with all warnings on, and forgot to include stdlib.h. malloc is then by some compilers interpreted to return int instead of void*. On a 64 bit architecture this looses significant information and thus at the end you see the same value in your print.

Don't cast the return of malloc.

Upvotes: 2

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