Reputation: 1948
From JavaScript is there a way to get list of days between two dates from MySQL format. I don't want to use any library for this. This is what i did.
function generateDateList(from, to) {
var getDate = function(date) { //Mysql Format
var m = date.getMonth(), d = date.getDate();
return date.getFullYear() + '-' + (m < 10 ? '0' + m : m) + '-' + (d < 10 ? '0' + d : d);
}
var fs = from.split('-'), startDate = new Date(fs[0], fs[1], fs[2]), result = [getDate(startDate)], start = startDate.getTime(), ts, end;
if ( typeof to == 'undefined') {
end = new Date().getTime();
} else {
ts = to.split('-');
end = new Date(ts[0], ts[1], ts[2]).getTime();
}
while (start < end) {
start += 86400000;
startDate.setTime(start);
result.push(getDate(startDate));
}
return result;
}
console.log(generateDateList('2014-2-27', '2014-3-2'));
I test it from chrome and nodejs below are the result.
[ '2014-02-27',
'2014-02-28',
'2014-02-29',
'2014-02-30',
'2014-02-31',
'2014-03-01',
'2014-03-02' ]
yeh big leap year:-D..., how can i fix this? or is there any better way.?
Upvotes: 6
Views: 21281
Reputation: 11465
if you have a large gap between the start and end date then using moment can be vital
var moment = require('moment');
function getDates(fromDate, toDate) {
const dateArray = [];
let currentDate = moment(fromDate);
const endDate = moment(toDate);
while (currentDate <= endDate) {
dateArray.push({
date: moment(currentDate).format('YYYY-MM-DD'),
month: moment(currentDate).month(),
day: moment(currentDate).day(),
});
currentDate = moment(currentDate).add(1, 'days');
}
return dateArray;
}
console.log(getDates(new Date('2018-01-01'), new Date('2028-07-01')));
output:
[
{ date: '2018-01-01', month: 0, day: 1 },
{ date: '2018-01-02', month: 0, day: 2 },
{ date: '2018-01-03', month: 0, day: 3 },
{ date: '2018-01-04', month: 0, day: 4 },
{ date: '2018-01-05', month: 0, day: 5 },
{ date: '2018-01-06', month: 0, day: 6 },
{ date: '2018-01-07', month: 0, day: 0 },
{ date: '2018-01-08', month: 0, day: 1 },
... 3765 more items
]
Upvotes: -1
Reputation: 285
const listDate = [];
const startDate ='2017-02-01';
const endDate = '2017-02-10';
const dateMove = new Date(startDate);
let strDate = startDate;
while (strDate < endDate) {
strDate = dateMove.toISOString().slice(0, 10);
listDate.push(strDate);
dateMove.setDate(dateMove.getDate() + 1);
};
Upvotes: 13
Reputation: 2814
I have used this one from https://flaviocopes.com/how-to-get-days-between-dates-javascript/
const getDatesBetweenDates = (startDate, endDate) => {
let dates = []
//to avoid modifying the original date
const theDate = new Date(startDate)
while (theDate < new Date(endDate)) {
dates = [...dates, new Date(theDate)]
theDate.setDate(theDate.getDate() + 1)
}
dates = [...dates, new Date(endDate)]
return dates
}
Invoke the function as follows:
getDatesBetweenDates("2021-12-28", "2021-03-01")
Note - I just had to fix issues with the Date object creation (new Date()) in the while loop and in the dates array. Other than that the code is pretty much same as seen on the above link
Upvotes: 3
Reputation: 5842
I expanded Công Thắng's great answer to return {years, months, days}, thought it was worth sharing:
function getDates(startDate, endDate) {
const days = [],
months = new Set(),
years = new Set()
const dateMove = new Date(startDate)
let date = startDate
while (date < endDate){
date = dateMove.toISOString().slice(0,10)
months.add(date.slice(0, 7))
years.add(date.slice(0, 4))
days.push(date)
dateMove.setDate(dateMove.getDate()+1) // increment day
}
return {years: [...years], months: [...months], days} // return arrays
}
console.log(getDates('2016-02-28', '2016-03-01')) // leap year
/* =>
{
years: [ '2016' ],
months: [ '2016-02', '2016-03' ],
days: [ '2016-02-28', '2016-02-29', '2016-03-01' ]
}
*/
const {months} = getDates('2016-02-28', '2016-03-01') // get only months
Basically the function just increments the built-in Date object by one day from start to end, while the Sets capture unique months and years.
Upvotes: 0
Reputation: 500
Take the start date and increment it by one day until you reach the end date.
Note: MySQL dates are standard format, no need to parse it by hand just pass it to the Date constructor:
new Date('2008-06-13')
.
const addDays = (date, days = 1) => {
const result = new Date(date);
result.setDate(result.getDate() + days);
return result;
};
const dateRange = (start, end, range = []) => {
if (start > end) return range;
const next = addDays(start, 1);
return dateRange(next, end, [...range, start]);
};
const range = dateRange(new Date("2014-02-27"), new Date("2014-03-02"));
console.log(range);
console.log(range.map(date => date.toISOString().slice(0, 10)))
Here I use a recursive function, but you could achieve the same thing using a while (see other answers).
Upvotes: 3
Reputation: 1
var oDate1 = oEvent.getParameter("from"),
oDate2 = oEvent.getParameter("to");
var aDates = [];
var currentDate = oDate1;
while (currentDate <= oDate2) {
aDates.push(new Date(currentDate));
currentDate.setDate(currentDate.getDate() + 1);
}
Upvotes: 0
Reputation: 161
dateRange(startDate, endDate) {
var start = startDate.split('-');
var end = endDate.split('-');
var startYear = parseInt(start[0]);
var endYear = parseInt(end[0]);
var dates = [];
for(var i = startYear; i <= endYear; i++) {
var endMonth = i != endYear ? 11 : parseInt(end[1]) - 1;
var startMon = i === startYear ? parseInt(start[1])-1 : 0;
for(var j = startMon; j <= endMonth; j = j > 12 ? j % 12 || 11 : j+1) {
var month = j+1;
var displayMonth = month < 10 ? '0'+month : month;
dates.push([i, displayMonth, '01'].join('-'));
}
}
return dates;
}
Upvotes: 0