CODEWITHSUNDEEP
pythonstringlistpython-2.7split
Nick
Nick

Reputation: 17

Python: Split string at the start of delimiter rather than the end

I'm trying to split a string using a multiple character delimiter, I can keep the delimiter in the result, but it is in the first part rather than the second part where I need it. This is what I have.

test = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ'
d = 'DEF'
for line in test:
    s = [e+d for e in test.split(d) if e !=""]
print s
['ABCDEF', 'GHIJKLMNOPQRSTUVWXYZDEF']

What I need is for the DEF at the split to be in part 2. I would appreciate any help.

Upvotes: 0

Views: 2377

Answers (3)

Hussain Shabbir
Hussain Shabbir

Reputation: 15015

Try like this:-

test = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ'
   words= list(word)
   first=[]
   second=[]
   for w in words:
      if w ==A or w==B or w==C:
        first.append(w)
      else:
        second.append(w)
   head='',join(first)
   tail='',join(second)
   [head,tail]

Upvotes: 0

Padraic Cunningham
Padraic Cunningham

Reputation: 180411

just add DEF to the second element:

s1,s2 = test.split(d)
print [s1,d + s2]

Or add inside the split list:

spl = test.split(d)
spl[-1] = d + spl[-1]

In your own code, you are just reassigning the value of s each time not adding to it so your loop is pointless:

for line in test:
    s = [e+d for e in test.split(d) if e !=""]

Upvotes: 0

falsetru
falsetru

Reputation: 369084

Using str.partition:

>>> test = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ'
>>> d = 'DEF'
>>> head, sep, tail = test.partition(d)
>>> [head, sep+tail]
['ABC', 'DEFGHIJKLMNOPQRSTUVWXYZ']

Upvotes: 1

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