CODEWITHSUNDEEP
phparrayskey
Jens Törnell
Jens Törnell

Reputation: 24768

Find array keys

In PHP I have an array that looks like this:

$array[0]['width'] = '100';
$array[0]['height'] = '200';
$array[2]['width'] = '150';
$array[2]['height'] = '250';

I want to add a new item after this, like this:

$array[]['width'] = '300';
$array[]['height'] = '500';

However the code above don't work, because it adds a new key for each row. It should be the same for the two rows above. A clever way to solve it?

An alternative solution would be to find the last key. I failed trying the 'end' function.

Upvotes: 1

Views: 2117

Answers (5)

Matijs
Matijs

Reputation: 2553

Another solution, useful when you cannot add both values in a single statement:

$a = array();
$array[] &= $a; // Append a reference to the array, instead of a copy

$a['width'] = '300';
$a['height'] = '500';

But you can also retrieve the last key in the array:

$array[]['width'] = '300';

end($array); // Make sure the internal array pointer is at the last item
$key = key($array);  // Get the key of the last item

$array[$key]['height'] = 300;

Upvotes: 2

zaf
zaf

Reputation: 23244

Or, just for completeness and obviousness, use a temporary array:

$t=array();
$t['width']='300';
$t['height']='500';

And then add it to the main array:

$array[]=$t;

Upvotes: 3

Arda Xi
Arda Xi

Reputation: 2666

If you don't mind it losing those keys, you could easily fix the problem by re-indexing.

$array = array_values($array);
$i = count($array);
$array[$i]['width'] = '300';
$array[$i]['height'] = '500';

However, if you don't want to do this, you could also use this:

$array[] = array(
    'width' => '300',
    'height' => '500'
);

Which will create a new array and inserts it as a second dimension.

Upvotes: 1

Matti Virkkunen
Matti Virkkunen

Reputation: 65126

How about

$array[] = array("width" => "300", "height" => "500");

Upvotes: 5

cletus
cletus

Reputation: 625087

The correct way to do this is:

$array[] = array(
  'width' => 200,
  'height' => 500,
);

because you're actually adding a new array to $array.

Upvotes: 9

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