CODEWITHSUNDEEP
network-programmingtcpdelayproductbandwidth
user2760642
user2760642

Reputation: 137

bandwidth delay product of a given link

i have been reading online about bandwidth delay and i couldn't understand.

Bandwidth delay is the max amount of data that the pipe can 'store'

But given a packet of size L is to be send over a link (A to B) with transmission rate of K-bps and bandwidth delay of P bits.

does that mean that the time i will take to sent from A to be will be (L/P)/K ?

L/P because i can only sent this amount of bits every single time and (/K) because i take this long to sent that amount each time?

Upvotes: 0

Views: 204

Answers (1)

user207421
user207421

Reputation: 311023

Think of it like a garden hose.

Delay is the length. That determines how long it takes one drop to get from one end to the other. Bandwidth is the cross-sectional area. That determines how many drops can travel together.

The product is volume, which corresponds to bandwidth-delay product, which corresponds to the total amount of water in the hose at any moment.

So if you have a full bucket of water and a funnel and you can pour it into the top of the hose, the total time for all the water to get to the other end is determined by

bucket capacity divided by volume

or

bucket capacity divided by (area multiplied by length)

or

bucket capacity divided by area divided by length

or

L/K/P

or

L/P/K

You can see that it doesn't matter which way around you do the divisions.

Upvotes: 1

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