CODEWITHSUNDEEP
pythonpython-2.7dictionary
sam1
sam1

Reputation: 21

Python Dictionary (Edit only values of Dictionary)

I am beginner with python. I have a list. I want to loop over values of list and add each to my dictionary values respectively. It looked simple but I tried to write few loops but none was working for me. For example

   Note :  Total number of element in My_list and total number of key:value pairs in My_Dict are same.

   My_list= [ [A,B,C], [D,E,F], [I,J,K] ]

   My_dict= { 'Apple'= {'Color'=[data1,data2]} , 'Orange'= {'Color'=[data3,data4]}, 'Peach'={ 'color'=[data5,data6]} }

I was trying to get following format by adding each element of My_list to respective value of dictionary.

  New_Dict=  { 'Apple'= { 'Name'=[A,B,C], 'Color'=[data1,data2]} , 'Orange'= { 'Name'=[D,E,F] ,'Color'=[data3,data4]}, 'Peach'={ 'Name'=[I,J,K], 'color'=[data5,data6]} }

Upvotes: 0

Views: 80

Answers (1)

dano
dano

Reputation: 94941

As suggested in the comments, you need to use a collections.OrderedDict instead of regular dict in order to preserve the ordering of my_dict. From there, you can use zip to iterate over the keys in my_dict and the elements of my_list in lockstep, and insert each item in my_list to the appropriate place in the OrderedDict:

from collections import OrderedDict

my_list = [['A', 'B', 'C'], ['D', 'E', 'F'], ['I', 'J', 'K']]
my_dict = OrderedDict([ 
    ('Apple', {'Color' : ['data1','data2']}), 
    ('Orange', {'Color' : ['data3','data4']}), 
    ('Peach', { 'color' : ['data5','data6']}), 
])

for key, name in zip(my_dict, my_list):
    my_dict[key]['Name'] = name

print(my_dict)

Output:

OrderedDict([('Apple', {'Color': ['data1', 'data2'], 'Name': ['A', 'B', 'C']}), ('Orange', {'Color': ['data3', 'data4'], 'Name': ['D', 'E', 'F']}), ('Peach', {'color': ['data5', 'data6'], 'Name': ['I', 'J', 'K']})])

Upvotes: 1

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