Reputation: 9559
I try to use Build.scala build multi-projects. This is my files directory:
MyMainPro/
app/
controls/
models/
views/
conf/
<some files>
modules/
anotherProject/
app/
controles/
models/
views/
conf/
<some files>
build.sbt
project/
<project build files>
Build.scala
<other directories>
I want invoke the variable inside the build.sbt from my outer Build.scala file. Is that Possible? How to do it.
For instance, my inner build.sbt have a project object:
lazy val pil = (project in file(".")).enablePlugins(PlayScala).settings(scalaVersion := "2.11.2")
How to invoke this project from my outer Build.scala file? I want to do similar like:
lazy val root = Project(appName, base = file(".")).enablePlugins(play.PlayScala)
.dependsOn(sil)
I just want to build my project depend on some OpenSource projects and want to change part of their source code.
I read the http://www.scala-sbt.org/0.13/tutorial/Multi-Project.html It is only contain how to get varieties from Build.scala to build.sbt. I want to do the opposite action. That is get varieties from buid.sbt to Build.scala.
Upvotes: 1
Views: 634
Reputation: 170859
No, you can't use values from build.sbt
. But for this case you don't need to; just write
lazy val root = Project(appName, base = file(".")).enablePlugins(play.PlayScala).
dependsOn(RootProject(file("modules/anotherProject")))
(see this answer for more information on source dependencies).
Upvotes: 2