Reputation: 357
I have a data set that looks like this:
Person Team
114 1
115 1
116 1
117 1
121 1
122 1
123 1
214 2
215 2
216 2
217 2
221 2
222 2
223 2
"Team" ranges from 1 to 33, and teams vary in terms of size (i.e., there can be 5, 6, or 7 members, depending on the team). I need to create a data set into something that looks like this:
1 1 1 1 1 1 1 0 0 0 0 0 0 0
1 1 1 1 1 1 1 0 0 0 0 0 0 0
1 1 1 1 1 1 1 0 0 0 0 0 0 0
1 1 1 1 1 1 1 0 0 0 0 0 0 0
1 1 1 1 1 1 1 0 0 0 0 0 0 0
1 1 1 1 1 1 1 0 0 0 0 0 0 0
1 1 1 1 1 1 1 0 0 0 0 0 0 0
0 0 0 0 0 0 0 1 1 1 1 1 1 1
0 0 0 0 0 0 0 1 1 1 1 1 1 1
0 0 0 0 0 0 0 1 1 1 1 1 1 1
0 0 0 0 0 0 0 1 1 1 1 1 1 1
0 0 0 0 0 0 0 1 1 1 1 1 1 1
0 0 0 0 0 0 0 1 1 1 1 1 1 1
0 0 0 0 0 0 0 1 1 1 1 1 1 1
The sizes of the individual blocks are given by the number of people in a team. How can I do this in R?
Upvotes: 0
Views: 257
Reputation: 13122
Another idea, although, I guess this is less efficient/elegant than RStudent's:
DF = data.frame(Person = sample(100, 21), Team = rep(1:5, c(3,6,4,5,3)))
DF
lengths = tapply(DF$Person, DF$Team, length)
mat = matrix(0, sum(lengths), sum(lengths))
mat[do.call(rbind,
mapply(function(a, b) arrayInd(seq_len(a ^ 2), c(a, a)) + b,
lengths, cumsum(c(0, lengths[-length(lengths)])),
SIMPLIFY = F))] = 1
mat
Upvotes: 1
Reputation: 9618
You could use bdiag
from the package Matrix
. For example:
> bdiag(matrix(1,ncol=7,nrow=7),matrix(1,ncol=7,nrow=7))
Upvotes: 2