CODEWITHSUNDEEP
c++
AnimatedLime
AnimatedLime

Reputation: 143

Outputting the score with only one function call

I'm trying to check the score and outputting who ever wins. Black > 0, White < 0, and a tie being == 0. What should I do to see if GetValue(board) == 0 without calling my function again or using another variable?

GetValue(board) > 0 ? cout << "Black wins" : cout << "White wins";

Upvotes: 0

Views: 86

Answers (3)

M.M
M.M

Reputation: 141618

std::string win_message(int const &x)
{
    if ( x == 0 ) return "Tie";
    if ( x < 0 ) return "Black wins";
    return "White wins";
}

// ...

    cout << win_message( GetValue(board) );

Upvotes: 1

BWG
BWG

Reputation: 2288

Why don't you want to use a variable ? If you do, you can use a compound ternary operator :

int val = GetValue(board);
cout << val == 0 ? "Tie" : (val < 0 ? "White wins" : "Black wins");

Edit: But THAT isn't one line, is it? The REAL one liner, courtesy of lambda functions.
It also assumes that GetValue returns an int. And requires a using namespace std for conciseness.

cout << vector<string>({"White wins", "Tie", "Black Wins"})[([](int x){return(0<x)-(x<0)+1;}(GetValue(board)))];

(Also don't actually use that)

Upvotes: 2

mrk
mrk

Reputation: 3191

If you want to output the score with one function call you can do something like:

cout << msg[ GetValue(board) + 1] << endl;

Where:

msg[0] = "White Wins";
msg[1] = "Tie";
msg[2] = "Black Wins";

This assumes that GetValue returns -1, 0, or 1;

Upvotes: 1

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