Reputation: 583
I have a scenario where I have Datagrid in my Silverlight application and I want the data to be exported to Power Point.
I researched and found only links, to export image(screen captured) to powerpoint. In my scenario , a screen capture also wont work as I have scroll bar with 20 columns and it is not getting displayed with the above solution.
Any work around for this scenario.
P.S : I do not intend to use any 3rd party controls.
Edit :
I have now tried to use OpenXML , but i am getting an error as below :
My code is as below :
using A = DocumentFormat.OpenXml.Drawing;
using P14 = DocumentFormat.OpenXml.Office2010.PowerPoint;
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using DocumentFormat.OpenXml;
using DocumentFormat.OpenXml.Packaging;
using DocumentFormat.OpenXml.Presentation;
using P = DocumentFormat.OpenXml.Presentation;
using D = DocumentFormat.OpenXml.Drawing;
using DocumentFormat.OpenXml.Drawing;
public static void CreateTableInLastSlide(PresentationDocument presentationDocument)
{
// Get the presentation Part of the presentation document
PresentationPart presentationPart = presentationDocument.PresentationPart;
// Get the Slide Id collection of the presentation document
var slideIdList = presentationPart.Presentation.SlideIdList;
if (slideIdList == null)
{
throw new NullReferenceException("The number of slide is empty, please select a ppt with a slide at least again");
}
// Get all Slide Part of the presentation document
var list = slideIdList.ChildElements
.Cast<SlideId>()
.Select(x => presentationPart.GetPartById(x.RelationshipId))
.Cast<SlidePart>();
// Get the last Slide Part of the presentation document
var tableSlidePart = (SlidePart)list.Last();
// Declare and instantiate the graphic Frame of the new slide
P.GraphicFrame graphicFrame = tableSlidePart.Slide.CommonSlideData.ShapeTree.AppendChild(new P.GraphicFrame());
ApplicationNonVisualDrawingPropertiesExtension applicationNonVisualDrawingPropertiesExtension = new ApplicationNonVisualDrawingPropertiesExtension();
P14.ModificationId modificationId1 = new P14.ModificationId() { Val = 3229994563U };
modificationId1.AddNamespaceDeclaration("p14", "http://schemas.microsoft.com/office/powerpoint/2010/main");
applicationNonVisualDrawingPropertiesExtension.Append(modificationId1);
graphicFrame.NonVisualGraphicFrameProperties = new DocumentFormat.OpenXml.Presentation.NonVisualGraphicFrameProperties
(new A.NonVisualDrawingProperties() { Id = 5, Name = "table 1" },
new A.NonVisualGraphicFrameDrawingProperties(new A.GraphicFrameLocks() { NoGrouping = true }),
new ApplicationNonVisualDrawingProperties(new ApplicationNonVisualDrawingPropertiesExtensionList(applicationNonVisualDrawingPropertiesExtension)));
graphicFrame.Transform = new Transform(new Offset() { X = 10, Y = 10 });
graphicFrame.Graphic = new A.Graphic(new A.GraphicData(GenerateTable()) { Uri = "http://schemas.openxmlformats.org/drawingml/2006/table" });
presentationPart.Presentation.Save();
}
private static A.Table GenerateTable()
{
string[,] tableSources = new string[,] { { "name", "age" }, { "Tom", "25" } };
// Declare and instantiate table
A.Table table = new A.Table();
// Specify the required table properties for the table
A.TableProperties tableProperties = new A.TableProperties() { FirstRow = true, BandRow = true };
A.TableStyleId tableStyleId = new A.TableStyleId();
tableStyleId.Text = "{5C22544A-7EE6-4342-B048-85BDC9FD1C3A}";
tableProperties.Append(tableStyleId);
// Declare and instantiate tablegrid and colums
A.TableGrid tableGrid1 = new A.TableGrid();
A.GridColumn gridColumn1 = new A.GridColumn() { Width = 3048000L };
A.GridColumn gridColumn2 = new A.GridColumn() { Width = 3048000L };
tableGrid1.Append(gridColumn1);
tableGrid1.Append(gridColumn2);
table.Append(tableProperties);
table.Append(tableGrid1);
for (int row = 0; row < tableSources.GetLength(0); row++)
{
// Instantiate the table row
A.TableRow tableRow = new A.TableRow() { Height = 370840L };
for (int column = 0; column < tableSources.GetLength(1); column++)
{
tableRow.Append(CreateTextCell(tableSources.GetValue(row, column).ToString()));
}
table.Append(tableRow);
}
return table;
}
Am i using the correct graphics and transform ?? The line which is causing the problem according to me is :
P.GraphicFrame graphicFrame = tableSlidePart.Slide.CommonSlideData.ShapeTree.AppendChild(new P.GraphicFrame());
As if i comment his line i dont get the error, but neither do i get the table :o/ Any help ?
Upvotes: 2
Views: 3993
Reputation: 583
Finally i was able to solve the problem using the Open XML productivity tool (here) . The line i highlighted was the error. I needed to add the below code :
List<OpenXmlElement> elements = new List<OpenXmlElement>();
elements.Add(new P.NonVisualGraphicFrameProperties
(new P.NonVisualDrawingProperties() { Id = 1, Name = "xyz" }, new P.NonVisualGraphicFrameDrawingProperties(),new ApplicationNonVisualDrawingProperties()));
P.GraphicFrame graphicFrame = tableSlidePart.Slide.CommonSlideData.ShapeTree.AppendChild(new P.GraphicFrame(elements));
Thus i was able to get output without any errors :)
Upvotes: 2