CODEWITHSUNDEEP
javaarraysobject
user3082928
user3082928

Reputation: 81

how to put array as an argument in java?

I have tried using array as parameter but when trying to put an array as an argument I get following error:

required: int,int[] found: int,int reason: actual argument int cannot be converted to int[] by method invocation conversion 2 errors

Source Code:

public class utopian{

    void height(int t,int[] n){

    n = new int[100];
    for (int i=0;i<t;i++){
        int k = n[i];
        if (k%2==0){
            for(int j=0;j<=k;j=j+2){
                int h=1;
                h=h*2;
                h=h+1;

            }}
            else{
                for(int j=0;j<=k;j=j+2){
                int h=1;
                h=h*2;
                h=h+1;

            }
           int h=h*2;    
            }
    System.out.println(h);  
            }        
    }

}

--

public class Solution {

    public static void main(String[] args) {
        utopian heht = new utopian();
        heht.height(2,{0,1})
}}

I want to use array as an argument and I cannot understand how.

Upvotes: 1

Views: 966

Answers (2)

Akash Thakare
Akash Thakare

Reputation: 23012

You can do it like this,

utopian heht = new utopian();
int array[]={0,1};//Declaration of array
heht.height(2,array)//pass array

Other than that inline declaration won't allow you to reuse the array.

heht.height(2, new int[] {0,1});//Here you can't reuse the array in further code
//if you don't want to reuse it than go for this

Upvotes: 0

Joop Eggen
Joop Eggen

Reputation: 109613

heht.height(2, new int[] {0,1})

However there are places for a less verbose notation, which probably misled you:

int[] data = {0, 1};

Upvotes: 2

Related Questions