CODEWITHSUNDEEP
pythonsshsubprocess
ayaan
ayaan

Reputation: 735

ssh with Subprocess.popen

Hello All i'm stuck with a small problem. May be i'm missing something obvious but i'm unable to figure out the problem. I've GUI where i have a button named "erp" and if i press that it should do an ssh first to a machine named (host id name) 'ayaancritbowh91302xy' and then it should execute commands like (cd change dir) and 'ls -l'. I've tried the following code:

def erptool():
    sshProcess = subprocess.Popen(['ssh -T', 'ayaancritbowh91302xy'],stdin=subprocess.PIPE, stdout = subprocess.PIPE)
    sshProcess.stdin.write("cd /home/thvajra/transfer/08_sagarwa\n")
    sshProcess.stdin.write("ls -l\n")
    sshProcess.stdin.write("echo END\n")
    for line in stdout.readlines():
        if line == "END\n":
        break
        print(line)

i got the following error:

Traceback (most recent call last):
  File "Cae_Selector.py", line 34, in erptool
    for line in stdout.readlines():
NameError: global name 'stdout' is not defined
Pseudo-terminal will not be allocated because stdin is not a terminal.

How to do this? can anyone help me with this?

Upvotes: 2

Views: 23262

Answers (3)

Nick Russo
Nick Russo

Reputation: 1542

Try this:

#!/usr/bin/env python
import subprocess
def erptool():
    sshProcess = subprocess.Popen(['ssh', '-T', 'ayaancritbowh91302xy'],
                                  stdin=subprocess.PIPE, stdout=subprocess.PIPE)
    out, err = sshProcess.communicate("cd /home/thvajra/transfer/08_sagarwa\nls -l\n")
    print(out),
erptool()

I added -T so ssh wouldn't try to allocate a pseudo-tty, and avoid END and stdout issues by using communicate.

Upvotes: 4

jfs
jfs

Reputation: 414225

To execute several shell commands via ssh:

#!/usr/bin/env python3
from subprocess import Popen, PIPE

with Popen(['ssh', '-T', 'ayaancritbowh91302xy'],
           stdin=PIPE, stdout=PIPE, stderr=PIPE,
           universal_newlines=True) as p:
    output, error = p.communicate("""            
        cd /home/thvajra/transfer/08_sagarwa
        ls -l
        """)
    print(output)
    print(error)
    print(p.returncode)

output contains stdout, error -- stderr, p.returncode -- exit status.

Upvotes: 3

user2879704
user2879704

Reputation:

It must be sshProcess.stdout.readLines() as you are talking to the process's stdout....

Upvotes: 0

Related Questions