CODEWITHSUNDEEP
javaphpjson
Nandan Bhat
Nandan Bhat

Reputation: 1563

JSON response is not working in PHP version 5.3.24

I am developing a Java application where I have to pass values to my server and receive the response from PHP file (version 5.3.24).The code is running fine in localhost and other live servers where the PHP version is greater than 5.3.24.

This is my Java code.

public static void send() {

try {
// make json string, try also hamburger
String json = "{\"name\":\"Frank\",\"food\":\"pizza\",\"quantity\":3}";

// send as http get request
URL url = new URL("http://www.matjazcerkvenik.si/php/json/pizzaservice.php?order="+json);
URLConnection conn = url.openConnection();

// Get the response
BufferedReader rd = new BufferedReader(new InputStreamReader(conn.getInputStream()));
String line;
while ((line = rd.readLine()) != null) {
System.out.println(line);
}
rd.close();
} catch (Exception e) {
e.printStackTrace();
}
}

public static void main(String[] args) {
send();
}

This is my PHP code.

<?php
$order = $_GET["order"];
$obj = json_decode($order);
$name = $obj -> {"name"};
$food = $obj -> {"food"};
$quty = $obj -> {"quantity"};
if ($food == "pizza") {
$price = 4000;
} else if ($food == "hamburger") {
$price = 5000;
} else {
$price = 0;
}
$price = $price * $quty;
if ($price == 0) {
$status = "not-accepted";
} else {
$status = "accepted";
}
$array = array("name" => $name, "food" => $food, "quantity" => $quty, "price" => $price, "status"     
=> $status);
echo json_encode($array);
?>

Upvotes: 0

Views: 184

Answers (1)

Jevgenijs Vaikulis
Jevgenijs Vaikulis

Reputation: 686

Change your php script a bit:

<?php
$order = get_magic_quotes_gpc() ? stripslashes($_GET["order"]) : $_GET["order"];
$obj = json_decode($order);
$name = $obj -> {"name"};
$food = $obj -> {"food"};
$quty = $obj -> {"quantity"};
if ($food == "pizza") {
$price = 4000;
} else if ($food == "hamburger") {
$price = 5000;
} else {
$price = 0;
}
$price = $price * $quty;
if ($price == 0) {
$status = "not-accepted";
} else {
$status = "accepted";
}
$array = array("name" => $name, "food" => $food, "quantity" => $quty, "price" => $price, "status"     
=> $status);
echo json_encode($array);
?>

Upvotes: 1

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