CODEWITHSUNDEEP
pythonlistconditional-statements
Milano
Milano

Reputation: 18745

Logic rules of Python's `if` clause

I have an if condition in my code which seems for example like this:

a = [1,2,3]
b = [4,5,6]
c = [7,8,9]

I want 'If' to return true when (1 is in a) or (1 is in b) or (1 is in c) or (5 is in a) or (5 is in b) or (5 is in c)

I've tried: 

if (1 or 5) in (a or b or c):
    pass

But this obviously didn't work that way. Could you give me a hint? Thanks

Upvotes: 0

Views: 73

Answers (2)

marceljg
marceljg

Reputation: 1067

This seems to work for me, though there might be a built in to concatenate the three lists.

a = [1,2,3]
b = [4,5,6]
c = [7,8,9]  
target = [1,5]

any(x for x in (a+b+c) if x in target)

True

Upvotes: 0

Veedrac
Veedrac

Reputation: 60167

You should probably use sets:

a = {1, 2, 3}
b = {4, 5, 6}
c = {7, 8, 9}

a | b | c
#>>> {1, 2, 3, 4, 5, 6, 7, 8, 9}

{1, 5} & (a | b | c)
#>>> {1, 5}

bool({1, 5} & (a | b | c))
#>>> True

if {1, 5} & (a | b | c):
    print("Yeah!")
#>>> Yeah!

if not {1, 5}.isdisjoint(a | b | c):
    print("Yeah!")    
#>>> Yeah!

If you want short-circuiting:

if not all({1, 5}.isdisjoint(items) for items in (a, b, c)):
    print("Yeah!")    
#>>> Yeah!

Upvotes: 2

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