CODEWITHSUNDEEP
pythonregex
user3590149
user3590149

Reputation: 1605

Python- Regex for dir of certain depth

I have a regex expression but its not working for all cases.

I need it to be able to match any case of the following within two levels of depth:

If this word "test_word" is in the statement return true

What I been using hasn't been working

('^/[^/]*/test_word/.+')

or

('^/test_word/.+')**

So I'm matching in statements with dirs such as:

/user/test_word
/test_word
/test_word/test_word/

but false in this example because its beyond two levels. I don't want positive for anything beyond two levels

   /something/something/test_word/

and anything you can think of that could happen.

Upvotes: 0

Views: 296

Answers (5)

user557597
user557597

Reputation:

For 2 levels 

^/(?:[^/\r\n]*/){0,1}test_word(?:/|$)

Expanded: 

 ^ 
 /
 (?: [^/\r\n]* / ){0,1}
 test_word
 (?: / | $ )

For N levels (>= 2) 

^/(?:[^/\r\n]*/){0,N-1}test_word(?:/|$)

Expanded: 

 ^ 
 /
 (?: [^/\r\n]* / ){0,N-1}
 test_word
 (?: / | $ )

Upvotes: 0

Jason Hu
Jason Hu

Reputation: 6333

i would recommend you not to use regex in such case. what you want here is partial perfect match instead of pattern match, so it's a waste of computation resource. you could do it by simply:

import os
filepath = #init
hier = filepath.split(os.path.sep)
print 'right' if hier[1] == 'test_word' or hier[2] == 'test_word' else 'wrong'

Upvotes: 1

Mark Tolonen
Mark Tolonen

Reputation: 177685

How about:

lines = '''\
/user/test_word
/test_word
/test_word/test_word/
/something/something/test_word/
/user/test_word/
/test_word/
/test_word/test_word
/something/something/test_word
/user/test_word/more
/test_word/more
/test_word/test_word/more
/something/something/test_word/more
/something/test_word/test_word
/test_wordxx
/something/test_wordxx
'''.splitlines()

import re
for line in lines:
    if re.match('/(?:[^/]+/)?test_word(?:/|$)',line):
        print('YES',line)
    else:
        print('NO ',line)

Output:

YES /user/test_word
YES /test_word
YES /test_word/test_word/
NO  /something/something/test_word/
YES /user/test_word/
YES /test_word/
YES /test_word/test_word
NO  /something/something/test_word
YES /user/test_word/more
YES /test_word/more
YES /test_word/test_word/more
NO  /something/something/test_word/more
YES /something/test_word/test_word
NO  /test_wordxx
NO  /something/test_wordxx

Not sure if you want the 3rd to last one.

Upvotes: 1

PVNRT
PVNRT

Reputation: 335

Assuming this is python 2.7 (haven't worked with 3) you don't really need any libraries just the builtin string functions this is how I approached it:

testword = "test_word"
stringToCheck = "/something/something/TeSt_wOrD/"

def testForWord(string):
    if testword in string.lower(): return True
    else: return False

print testForWord(stringToCheck)

As you can see it checks for any case because it just checks when all cases are lower case. I'm not 100% sure if thats what you need but I think that should do it :D.

Upvotes: 1

Avinash Raj
Avinash Raj

Reputation: 174706

I think you want something like this,

^(?=.*?/test_word)(?!.*?//)\/(?:[^/]*)(?:/[^/]*)?/?$

DEMO

Upvotes: 2

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