CODEWITHSUNDEEP
assemblymipsqtspim
Heyya
Heyya

Reputation: 193

Cannot print out integer in MIPS Assembly program

I am using QTSpim as my MIPS simulator and am having a hard time figuring out how to print out an integer that the user input. So far, my code is:

.data
prompt: .asciiz "Please enter an integer: "

.text
main:
li $v0, 4
la $a0, prompt
syscall

li $v0, 5
move $s0, $v0
syscall

li $v0, 5
move $s1, $v0
syscall

li $v0, 5
move $s2, $v0
syscall

jal order3

li $v0, 1
move $a0, $s0
syscall

li $v0, 10
syscall


swap:
move $t0, $a0
move $a0, $a1
move $a1, $t0
jr $ra

swap1:
move $t0, $a1
move $a1, $a2
move $a2, $t0
jr $ra

order3:
bgt $a0, $a1, swap
bgt $a1, $a2, swap1
bgt $a0, $a1, swap
jr $ra

Every time I try to print out my first integer, it prints out a 5, which it shouldn't. I do not know why this is happening. If anyone could point out the flaw in my code that would be great.

Thanks.

Upvotes: 1

Views: 398

Answers (1)

Michael
Michael

Reputation: 58507

You're trying to use the result of a syscall before the syscall has been performed:

li $v0, 5
move $s0, $v0
syscall

That should be:

li $v0, 5
syscall
move $s0, $v0

Same for the other two read_int syscalls.

Then there's also the fact that your order3 routine is checking/altering $a0..$a2, while your numbers are in $s0..$s2.

Upvotes: 1

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