Reputation: 323
I have a data frame which looks like this:
id score
1 15
1 18
1 16
2 10
2 9
3 8
3 47
3 21
I'd like to identify a way to flag the first occurrence of id -- similar to first. and last. in SAS. I've tried the !duplicated function, but I need to actually append the "flag" column to my data frame since I'm running it through a loop later on. I'd like to get something like this:
id score first_ind
1 15 1
1 18 0
1 16 0
2 10 1
2 9 0
3 8 1
3 47 0
3 21 0
Upvotes: 7
Views: 3493
Reputation: 226332
Using plyr
:
library("plyr")
ddply(x,"id",transform,first=as.numeric(seq(length(score))==1))
or if you prefer dplyr
:
x %>% group_by(id) %>%
mutate(first=c(1,rep(0,n-1)))
(although if you're operating completely in the plyr
/dplyr
framework you probably wouldn't need this flag variable anyway ...)
Upvotes: 3
Reputation: 70286
Another base R option:
df$first_ind <- ave(df$id, df$id, FUN = seq_along) == 1
df
# id score first_ind
#1 1 15 TRUE
#2 1 18 FALSE
#3 1 16 FALSE
#4 2 10 TRUE
#5 2 9 FALSE
#6 3 8 TRUE
#7 3 47 FALSE
#8 3 21 FALSE
This also works in case of unsorted id
s. If you want 1/0 instead of T/F you can easily wrap it in as.integer(.)
.
Upvotes: 2
Reputation: 70633
You can find the edges using diff
.
x <- read.table(text = "id score
1 15
1 18
1 16
2 10
2 9
3 8
3 47
3 21", header = TRUE)
x$first_id <- c(1, diff(x$id))
x
id score first_id
1 1 15 1
2 1 18 0
3 1 16 0
4 2 10 1
5 2 9 0
6 3 8 1
7 3 47 0
8 3 21 0
Upvotes: 6
Reputation: 61164
> df$first_ind <- as.numeric(!duplicated(df$id))
> df
id score first_ind
1 1 15 1
2 1 18 0
3 1 16 0
4 2 10 1
5 2 9 0
6 3 8 1
7 3 47 0
8 3 21 0
Upvotes: 17