Reputation: 25
Given following classes:
class Person(models.Model):
person_id = models.IntegerField(primary_key=True)
name = models.CharField(max_length=45)
class Person_Preference(models.Model):
person_id = models.ForeignKey(Person, db_column='person_id')
preference_type = models.CharField(max_length=255, blank=False)
preference_value = models.CharField(max_length=255, blank=False)
class Car(models.Model):
car_id = models.IntegerField(primary_key=True)
name = models.CharField(max_length=45)
class Car_Feature(models.Model):
car_id = models.ForeignKey(Car, db_column='car_id')
feature_type = models.CharField(max_length=255, blank=False)
feature_value = models.CharField(max_length=255, blank=False)
Tables Example
Person
---------
1 | Peter
Person_Preference
--------------------
1 | luxury | cooling
1 | safety | crash-proof
1 | luxury | heated seats
Car
----------
1 | Ford
Car_Feature
-----------------
1 | electronic | air-con
1 | verified | air-bag
1 | electronic | headed seats
I would like to create a recommendation class that link a person's preferences to car features together, i.e.:
class Recommendation(models.Model):
preference_type = models.ManyToManyField('Person_Preference')
preference_value = models.ManyToManyField('Person_Preference')
feature_type = models.ManyToManyField('Car_Feature')
feature_value = models.ManyToManyField('Car_Feature')
Tables Example
Recommendation
---------
luxury | cooling | electronic | air_con
I realized I can't do this because there are 2 attributes referencing the same class in ManyToManyField Person_Preference and also for Car_Features.
Does this mean there isn't a way to do a Many-To-Many relationship with a class that is depended on 2 attributes? Thus would the only method to resolve the above is to create a separate class for each particular preference_type and feature_type?
Updated on Oct 11, 2014
To better illustrate my problem (I am a beginner in Django, but more proficient in SQL), I am trying to write a Django version of SQL that can allow me to look up the recommendation table using preference_type as the first argument, and preference_value as the second argument:
SELECT *
FROM Recommendation
WHERE preference_type = 'luxury'
AND preference_value = 'cooling'
I know the above can be achieved using Django's QuerySet filters, though I am trying to take advantage of the Many-to-many relationship because it seems (to my limited Model knowledge) this is the correct thing to do in Django. Though perhaps I am wrong about this? If anyone has a good reference to how to create Django Models then please also let me know. (I have read the official Django doc many times though I am still confused)
Thank you very much for your help.
Upvotes: 0
Views: 1449
Reputation: 1914
You can have multiple M2M with the same class, you just have to add a related_name
parameter like so:
class Recommendation(models.Model):
preference_type = models.ManyToManyField('Person_Preference', related_name='foo')
preference_value = models.ManyToManyField('Person_Preference', related_name='bar')
...
EDIT
For your situation, just do this:
class Recommendation(models.Model):
#I believe convention for m2m is to pluralize the field name
preferences = models.ManyToManyField('Person_Preference')
Your query would be:
Recommendation.objects.filter(preferences__type='luxury', preferences__value='cooling')
EDIT 2
Here is a more detailed example:
Models:
class Preference(CommonModel):
type = models.CharField(max_length=250, null=True, blank=True)
value = models.CharField(max_length=250, null=True, blank=True)
class Recommendation(CommonModel):
name = models.CharField(max_length=250, null=True, blank=True)
preferences = models.ManyToManyField(Preference, null=True, blank=True)
def __unicode__(self):
return self.name
In the Django shell:
p1 = Preference.objects.create(type='foo', value='bar')
p2 = Preference.objects.create(type='foo')
p3 = Preference.objects.create(value='bar')
r1 = Recommendation.objects.create(name='foobar')
r1.preferences.add(p1)
r2 = Recommendation.objects.create(name='foo')
r2.preferences.add(p2)
r3 = Recommendation.objects.create(name='bar')
r3.preferences.add(p3)
>>> Recommendation.objects.filter(preferences__type='foo')
[<Recommendation: foobar>, <Recommendation: foo>]
>>> Recommendation.objects.filter(preferences__value='bar')
[<Recommendation: foobar>, <Recommendation: bar>]
>>> Recommendation.objects.filter(preferences__type='foo', preferences__value='bar')
[<Recommendation: foobar>]
Upvotes: 1