CODEWITHSUNDEEP
pythonmatplotlibviolin-plot
user2489252
user2489252

Reputation:

Changing the color of matplotlib's violin plots

Is there a way to change the color of the violin plots in matplotlib?

The default color is this "brownish" color, which is not too bad, but I'd like to color e.g., the first 3 violins differently to highlight them. I don't find any parameter in the documentation. Any ideas or hacks to color the violins differently?

enter image description here

Upvotes: 35

Views: 39696

Answers (3)

mohammadali
mohammadali

Reputation: 69

Suppose you have 3 vectors: data1, data2, data3; and you have plotted your matplotlib violinplots in one figure; then, to set the color of the median line and body facecolor specific for each sub-violinplot you can use:

colors = ['Blue', 'Green', 'Purple']

# Set the color of the violin patches
for pc, color in zip(plots['bodies'], colors):
    pc.set_facecolor(color)

# Set the color of the median lines
plots['cmedians'].set_colors(colors)

The full example:

# Set up the figure and axis
fig, ax = plt.subplots(1, 1)

# Create a list of the data to be plotted
data = [data1, data2, data3]

# Set the colors for the violins based on the category
colors = ['Blue', 'Green', 'Purple']

# Create the violin plot
plots = ax.violinplot(data, vert=False, showmedians=True, showextrema=False, widths=1)

# Set the color of the violin patches
for pc, color in zip(plots['bodies'], colors):
    pc.set_facecolor(color)

# Set the color of the median lines
plots['cmedians'].set_colors(colors)

# Set the labels
ax1.set_yticks([1, 2, 3], labels=['category1', 'category2', 'category3'])

ax1.invert_yaxis() # ranking from top to bottom: invert yaxis

plt.show()

Example for matplotlib violin plots with different colors

Upvotes: 4

Joel Bondurant
Joel Bondurant

Reputation: 883

import numpy as np
import matplotlib.pyplot as plt
%matplotlib inline

rrred = '#ff2222'
bluuu = '#2222ff'
x = np.arange(2, 25)
y = np.array([xi * np.random.uniform(0, 1, 10**3) for xi in x]).T

# Create violin plot objects:
fig, ax = plt.subplots(1, 1, figsize = (8,8))
violin_parts = ax.violinplot(y, x, widths = 0.9, showmeans = True, showextrema = True, showmedians = True)

# Make all the violin statistics marks red:
for partname in ('cbars','cmins','cmaxes','cmeans','cmedians'):
    vp = violin_parts[partname]
    vp.set_edgecolor(rrred)
    vp.set_linewidth(1)

# Make the violin body blue with a red border:
for vp in violin_parts['bodies']:
    vp.set_facecolor(bluuu)
    vp.set_edgecolor(rrred)
    vp.set_linewidth(1)
    vp.set_alpha(0.5)

enter image description here

Upvotes: 18

Nick T
Nick T

Reputation: 26717

matplotlib.pyplot.violinplot() says it returns:

A dictionary mapping each component of the violinplot to a list of the corresponding collection instances created. The dictionary has the following keys:

  • bodies: A list of the matplotlib.collections.PolyCollection instances containing the filled area of each violin.
  • [...among others...]

Methods of PolyCollections include:

So, it looks like you could just loop through the result's body list and modify the facecolor of each:

violin_parts = plt.violinplot(...)

for pc in violin_parts['bodies']:
    pc.set_facecolor('red')
    pc.set_edgecolor('black')

It is a bit strange though that you can't set this when creating it like the common plot types. I'd guess it's probably because the operation creates so many bits (the aforementioned PolyCollection along with 5 other LineCollections), that additional arguments would be ambiguous.

Upvotes: 52

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