CODEWITHSUNDEEP
shellsh
aiman
aiman

Reputation: 1103

Sh shell scripting optional arguments not getting read

In my shell script, I am reading two optional parameters. The first parameter is not getting read. Given below is the code: 

#! /bin/sh  
while getopts "f:c:" opt;  
do  
case "${opt}" in  
f) file=${OPTARG}   
echo "" "File Name: ${file}"  
;;  
c) str=${OPTARG}  
echo "" "String: ${str}"  
;;  
esac    
done

When I am running my script: 

$ sh myscript.sh -f filename.txt -c someString

Output:

$ File Name:  
$ String: someString

Please let me know where am i going wrong. I have tried all options in getopts: 

:f:c  
f:c  
f:c:  
:f:c:

Upvotes: 0

Views: 138

Answers (1)

Ajay
Ajay

Reputation: 785

You code is not working because of typo c) str=${OPTAGR} echo "" "String: ${str}" ;; here above you have typo in str=${OPTAGR} it should be str=${OPTARG} I have executed below piece of code and it worked fine

#! /bin/sh
while getopts "f:c:" opt;
do
case "${opt}" in
f) file=${OPTARG}
echo "" "File Name: ${file}"
;;
c) str=${OPTARG}
echo "" "String: ${str}"
;;
esac
done

Output

ajay@Ajay:~$ ./new.sh -f filename.txt -c sometext
File Name: filename.txt
String: sometext

Upvotes: 1

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