CODEWITHSUNDEEP
phparrays
Aswin
Aswin

Reputation: 349

array_rand() expects parameter 1 to be array

I tried the below code for print a random value from an array for 70 times but i am getting an error as such : ' array_rand() expects parameter 1 to be array'.

$q= array("top","below","right","left");
function ran(){
    $rand_keys = array_rand($q, 1);
    return $rand_keys[0];
}

for ($m=0; $m <70 ; $m++) {
    ran($q);
    echo ran();   
}

Upvotes: 0

Views: 2098

Answers (2)

Yoric
Yoric

Reputation: 1784

Yes, add $q as a parameter. Also, you should return the value of $q at index $rand_key. You kinda miss used array_rand return value.

Giving you this code :

$q = array("top","below","right","left");

for ($m = 0; $m <70 ; $m++) { 
    echo ran($q).' ';
}

function ran($q){
   $rand_keys = array_rand($q, 1);
   return $q[$rand_keys];
}

Upvotes: 1

Barmar
Barmar

Reputation: 781004

Global variables are not normally visible inside functions. You should put $q in the function parameter list:

function ran($q) {
    $rand_keys = array_rand($q, 1);
    return $rand_keys[0];
}

Then call it as:

echo ran($q);

Upvotes: 3

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