CODEWITHSUNDEEP
javaregex
Sstx
Sstx

Reputation: 604

Java how to using Regex mask numberic as I expected

Suggest I have follow two values:

       123456789
       123456789111

Does String.replaceAll can do follow?

       123456789           ->    XXXXXX789
       123456789111        ->    XXXXXXXXX111

for mask last three numberic, but replace other characters to X? Please noted the count of X in sample.

Thanks in advance.

Upvotes: 1

Views: 1057

Answers (3)

Avinash Raj
Avinash Raj

Reputation: 174706

Yes, replaceAll function will do this job.

String s1 = "123456789";
String s2 = "123456789111";
System.out.println(s1.replaceAll("\\d(?=\\d{3})", "X"));
System.out.println(s2.replaceAll("\\d(?=\\d{3})", "X"));

Output:

XXXXXX789
XXXXXXXXX111

Explanation:

  • \\d(?=\\d{3}) Match a digit only if it's followed by three digits. So it fails for last three digits. Finally all the matched digits are replaced by the letter X

Upvotes: 3

TheLostMind
TheLostMind

Reputation: 36304

Yes you can:

public static void main(String[] args) {
    String s1 = "123456789";
    String s2 = "123456789111";
    String regex = "\\d(?=\\d{3})"; // each digit followed by exactly 3 digits should be replaced by X
    System.out.println(s1.replaceAll(regex, "X"));
    System.out.println(s2.replaceAll(regex, "X"));

}

O/P :

XXXXXX789
XXXXXXXXX111

Upvotes: 0

vks
vks

Reputation: 67968

.(?!.{0,2}$)

Try this.Replace by X.Put flags m and g.See demo.

http://regex101.com/r/sK8oK9/2

Upvotes: 1

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