CODEWITHSUNDEEP
iosswiftcgfloat
Riyazul Aboobucker
Riyazul Aboobucker

Reputation: 496

"'CGFloat' is not convertible to 'Double'" error in Swift (iOS)

I'm trying to cut an image into 9 pieces in Swift. I'm getting this error:

'CGFloat' is not convertible to 'Double'

I get this error when I put i or j in the two variables.

Below is part of the code used for cutting the image.

for i in 1...3
    {
        for j in 1...3
        {
            var intWidth = ( i * (sizeOfImage.width/3.0))
            var fltHeight = ( j * (sizeOfImage.height/3.0))
        var portion = CGRectMake(intWidth,fltHeight, sizeOfImage.width/3.0, sizeOfImage.height/3.0);
            .
            .
      "Code goes on"

What is the problem?

Upvotes: 2

Views: 4076

Answers (2)

Pranav Kasetti
Pranav Kasetti

Reputation: 9925

This is a non-starter in Swift 5.5 (automatic conversion). We can pass CGFloat and Double interchangeably to functions that accept either of those types.

Upvotes: 0

Antonio
Antonio

Reputation: 72760

In swift there is no implicit conversion of numeric data types, and you are mixing integers and floats. You have to explicitly convert the indexes to CGFloats:

var intWidth = ( CGFloat(i) * (sizeOfImage.width/3.0))
var fltHeight = ( CGFloat(j) * (sizeOfImage.height/3.0))

As often happening in swift, the error message is misleading - it says:

'CGFloat' is not convertible to 'Double'

whereas I'd expect:

'CGFloat' is not convertible to 'Int'

Upvotes: 3

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