Reputation: 474
Print a triangular pattern of asterisks
I am required to use nested for loops and print('*', end=' ') to create the pattern shown here:
And here is my code. I have figured out the first two.
n = 0
print ("Pattern A")
for x in range (0,11):
n = n + 1
for a in range (0, n-1):
print ('*', end = '')
print()
print ('')
print ("Pattern B")
for b in range (0,11):
n = n - 1
for d in range (0, n+1):
print ('*', end = '')
print()
print ('')
When i start pattern C and D, i try the following:
print ("Pattern C")
for e in range (11,0,-1):
n = n + 1
for f in range (0, n+1):
print ('*', end = '')
print()
print ('')
print ("Pattern D")
for g in range (11,0,-1):
n = n - 1
for h in range (0, n-1):
print ('*', end = '')
print()
But the result is the same as A and B. Help is appreciated!
Upvotes: 3
Views: 63837
Answers (15)
Reputation: 782
var n = 5;
for(int row = 0 ; row < n; row++)
{
for(int col = 1; col <= n; col++)
{
if(col < n - row)
{
Console.Write(" ");
}
else
{
Console.Write("*");
}
}
Console.WriteLine();
}
(D)
Upvotes: 1
Reputation: 391
Try this one!
a)
*
**
***
****
*****
public class Main {
public static void main(String[] args) {
int n=5;
for(int i=1;i<=n;i++)
{
for(int j=1;j<=i;j++)
{
System.out.print("*");
}
System.out.println();
}
}
}
b)
*****
****
***
**
*
public class Main {
public static void main(String[] args) {
int n=5;
for(int i=1;i<=n;i++)
{
for(int j=1;j<=(i-1);j++)
{
System.out.print(" ");
}
for(int j=i;j<=n;j++)
{
System.out.print("*");
}
System.out.println();
}
}
}
c)
*
**
***
****
*****
public class Main
{
public static void main(String[] args)
{ int n=5;
for(int i=n;i>0;i--)
{
for(int j=1;j<=(i-1);j++)
{
System.out.print(" ");
}
for(int j=i;j<=n;j++)
{
System.out.print("*");
}
System.out.println();
}
}
}
d)
*****
****
***
**
*
public class Main
{
public static void main(String[] args) {
int n=5;
for(int i=n;i>0;i--)
{
for(int j=1;j<=i;j++)
{
System.out.print("*");
}
System.out.println();
}
}
}
Upvotes: 1
Reputation: 11
Pattern 1
for x in range(1,11):
print("*"*x)
Output
*
**
***
****
*****
******
*******
********
*********
**********
Pattern 2
for x in range(10,0,-1):
print("*"*x)
Output
**********
*********
********
*******
******
*****
****
***
**
*
Pattern 3
i=0
for x in range(10,0,-1):
print(" "*i,end="")
print("*"*x)
i+=1
Output
**********
*********
********
*******
******
*****
****
***
**
*
Pattern 4
i=10
for x in range(1,11):
print(" "*i,end="")
print("*"*x)
i-=1
Output
*
**
***
****
*****
******
*******
********
*********
**********
Upvotes: 1
Reputation: 53
The function:
def arrow(my_char, max_length):
for i in range(max_length*2):
if i <= max_length:
print(my_char*i)
if i > max_length:
print(my_char*(max_length*2-i))
The main():
def main():
print(arrow('*', 8))
if __name__ == "__main__":
main()
Output:
*
**
***
****
*****
******
*******
********
*******
******
*****
****
***
**
*
Upvotes: 1
Reputation: 41
for i in range(0,5):
for j in range(0,i+1):
print("*",end="")
print()
for k in range(5,0,-1):
for l in range(k-1,0,-1):
print("*",end="")
print()
*
**
***
****
*****
****
***
**
*
Upvotes: 1
Reputation: 11
using spaces you can create different- different patterns: 1.
def pattern(limit):
for i in range(limit+1):
print((limit-i)*" "+ ' #'*i)
pattern(4)
Output:
#
# #
# # #
# # # #
2.remove one space from above code and pattern will be changed in a pyramid
def pattern(limit):
for i in range(limit+1):
print((limit-i)*" "+ ' #'*i)
pattern(4)
output: #
# #
# # #
# # # #
3: no space print((limit-i)*""+ ' #'*i) will create
#
# #
# # #
# # # #
Upvotes: 1
Reputation: 61
print("Pattern C")
n=int(input("Enter number of rows: "))
for i in range (n,0,-1):
print((n-i) * ' ' + i * '*')
Upvotes: 2
Reputation: 4829
Pythonic way of doing this. Just 1 line of code (using list comprehension) for each pattern.
n = 10
# for A
print('\n'.join(['*'*i for i in range(1,n+1)]))
#output
*
**
***
****
*****
******
*******
********
*********
**********
# for B
print('\n'.join(['*'*i for i in range(n+1,0,-1)]))
#output
***********
**********
*********
********
*******
******
*****
****
***
**
*
# for C
print('\n'.join([' '*(n-i) + '*'*i for i in range(n,0,-1)]))
#output
**********
*********
********
*******
******
*****
****
***
**
*
# for D
print('\n'.join([' '*(n-i) + '*'*i for i in range(1,n+1)]))
#output
*
**
***
****
*****
******
*******
********
*********
**********
Upvotes: 2
Reputation: 11
def fun (n):
return n
n=int(raw_input("Enter the number"))
print "The given number is",n
for i in range (n,0,-1):
print "*"*i
output:
The given number is 3
***
**
*
Upvotes: 1
Reputation: 21
for i in range (1,n): # loop will execute from 1 to 4(n-1)
for j in range(1,i+1):
print("*",end="")
print()
for i in range (n+1,1,-1):
for j in range(i,1,-1):
print("*",end="")
print()
using for loop
Upvotes: 1
Reputation: 21
i=0
while(i<5):
j=0
while(j<=i):
print("*",end="") #end="" is given to stay on same line
j=j+1
print("") #it will take u to new line
i=i+1
j=0
i=i-2
j=i
while(i>=0):
while(j>=0):
print("*",end="")
j=j-1
print() #will also work
i=i-1
j=i
this will also work
Upvotes: 1
Reputation: 796
learn an easy way:
code1:
for n in range(0,5):
n +=1
print ("*" *(0+n))
what it does:
- for n in range(0,5): --> call a range of no of times you want loop to execute
- increment value of int n by one, so starting from range 0 to 5 every time for loop runs it increments int n by 1
- now print string "" and multiply it by value of int n+0, So when int n=0 as per logic int n increments by 1 and print ("" (0+n)) = print ("" *(0+1)) = *
output:
*
**
***
****
*****
code2:
for n in range(-5,0):
n +=1
print ("*" *(0-n+1))
output:
****
***
**
*
Upvotes: 1
Reputation: 164
for i in range(1,n+1): print '{:>{}}'.format('#'*i, n)
this is For pattern D
for i in range(1,n-1): print '{:>{}}'.format('#'*i, n)
this is For pattern c
Upvotes: 3
Reputation: 113844
Both patterns C and D require leading spaces and you are not printing any spaces, just stars.
Here is alternative code that prints the required leading spaces:
print ("Pattern C")
for e in range (11,0,-1):
print((11-e) * ' ' + e * '*')
print ('')
print ("Pattern D")
for g in range (11,0,-1):
print(g * ' ' + (11-g) * '*')
Here is the output:
Pattern C
***********
**********
*********
********
*******
******
*****
****
***
**
*
Pattern D
*
**
***
****
*****
******
*******
********
*********
**********
In more detail, consider this line:
print((11-e) * ' ' + e * '*')
It prints (11-e) spaces followed by e stars. This provides the leading spaces needed to make the patterns.
If your teacher wants nested loops, then you may need to convert print((11-e) * ' ' + e * '*') into loops printing each space, one at a time, followed by each star, one at a time.
Pattern C via nested loops
If you followed the hints I gave about nested loops, you would have arrived at a solution for Pattern C like the following:
print ("Pattern C")
for e in range (11,0,-1):
#print((11-e) * ' ' + e * '*')
for d in range (11-e):
print (' ', end = '')
for d in range (e):
print ('*', end = '')
print()
Upvotes: 4
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