Reputation: 26341
I have a plugin called "myPlugin" which uses the commonly used design pattern of default values which can be overridden upon initialization.
Instead of passing the overriding values upon initialization, I would like to extend the plugin as "myPlugin2" and change the default values so that when I initiate the extended plugin, it already has the desired new default values.
I've played around with adding new methods to the extended plugin, but I can't figure out how to change the default values.
In other words, I want the two lines of code to provide identical results.
$("body").myPlugin({'prop1':'prop1 modified','default_func4':function () {console.log('default_func4 modified')}});
$("body").myPlugin2();
How can I extend a jQuery plugin and change the default values?
http://jsfiddle.net/L1ng37wL/2/
<!DOCTYPE html>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
<title>Testing</title>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.js" type="text/javascript"></script>
<style type="text/css">
</style>
<script type="text/javascript">
(function ($) {
var defaults = {
'prop1' : 'prop1',
'default_func4' : function () {console.log('default_func4');},
'default_func5' : function () {console.log('default_func5');}
};
var methods = {
init: function (options) {
console.log("init");
console.log('defaults',defaults);
console.log('options',options);
var settings = $.extend({}, defaults, options);
console.log('settings',settings);
console.log('The value of "prop1" is '+settings.prop1);
settings.default_func4.call()
},
func1: function () {console.log("func1");},
func2: function () {console.log("func2");}
};
$.fn.myPlugin = function (method) {
// Method calling logic
if (methods[method]) {
return methods[method].apply(this, Array.prototype.slice.call(arguments, 1));
} else if (typeof method === 'object' || !method) {
return methods.init.apply(this, arguments);
} else {
$.error('Method ' + method + ' does not exist');
}
};
})(jQuery);
(function ($) {
var methods = {
'func1': function () {console.log("myPlugin2: func1");},
'func3': function () {console.log("myPlugin2: func3");}
}
$.fn.myPlugin2 = function (method) {
//HOW DO I CHANGE defaults.prop1 and defaults.default_func5?????
// Method calling logic
if (methods[method]) {
return methods[method].apply(this, Array.prototype.slice.call(arguments, 1));
} else if ((typeof method === 'object' || !method) && methods.init) {
return methods.init.apply(this, arguments);
} else {
try {
return $.fn.myPlugin.apply(this, arguments);
} catch (e) {
$.error(e);
}
}
}
})(jQuery);
$(function(){
$("body").myPlugin({
'prop1':'prop1 modified',
'default_func4':function () {console.log('default_func4 modified')}
});
$("body").myPlugin2();
//$("body").myPlugin2('func1');
//$("body").myPlugin2('func2');
//$("body").myPlugin2('func3');
});
</script>
</head>
<body>
</body>
</html>
Upvotes: 0
Views: 529
Reputation: 304
The double check on the method parameter feels a bit weird to me, but if I replace your single line in the try-block to the code below, the thing works like it should, while still allowing you to supply an object with even different options.
var args = arguments;
if (typeof method === 'object' || !method) {
// Fill args with the new defaults.
args = {
'prop1': 'prop1 modified',
'default_func4': function () {
console.log('default_func4 modified')
}
};
$.extend(args, method);
args = [args];
}
return $.fn.myPlugin.apply(this, args);
Upvotes: 1