CODEWITHSUNDEEP
shellpathreadlink
Miguel
Miguel

Reputation: 69

Why does not the readlink show the full path?

I'm making a shell script to search for files with a specific name and show their full path and size.

For example:

/home/miglui/Desktop/SO/teste/1/teste.txt: 14 bytes

The code of the segment that I'm having trouble is the next:

for i in `find $1 -name $4 -type f -printf "%s "` ; do
    path=`readlink -f $4`
    echo "$path: $i bytes"
done

The code returns:

/home/miglui/Desktop/SO/teste.txt: 14 bytes
/home/miglui/Desktop/SO/teste.txt: 48 bytes
/home/miglui/Desktop/SO/teste.txt: 29 bytes

But should return:

/home/miglui/Desktop/SO/teste/1/teste.txt: 14 bytes
/home/miglui/Desktop/SO/teste/2/teste.txt: 48 bytes
/home/miglui/Desktop/SO/teste/teste.txt: 29 bytes

What can be the problem?

Upvotes: 0

Views: 373

Answers (2)

John Bollinger
John Bollinger

Reputation: 181104

The problem is that every iteration of the loop prints argument 4 ($4) of the script. That has nothing to do with the results of your find. Perhaps you want something more like this:

while read size name; do
    path=`readlink -f $name`
    echo "$path: $size bytes"
done < `find $1 -name $4 -type f -printf '%s %h/%f\n'`

Upvotes: 1

glenn jackman
glenn jackman

Reputation: 247042

You are retrieving the size of 3 different files, but only reporting the name of the parameter you pass in.

Try this:

( cd -P -- "$1" && find "$(pwd -P)" -name "$4" -type f -printf "$p: %s bytes\n" )
  • run in a subshell so the cd does not affect the current shell.

Upvotes: 0

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