Reputation: 47
So here's my code to draw a triangle:
Graphics y = CreateGraphics();
Pen yy = new Pen(Color.Red);
pictureBox1.Refresh();
Point x = new Point(Convert.ToInt32(textBox1.Text)*10, Convert.ToInt32(textBox2.Text)*10);
Point xx = new Point(Convert.ToInt32(textBox3.Text)*10, Convert.ToInt32(textBox4.Text)*10);
Point xxx = new Point(Convert.ToInt32(textBox5.Text)*10, Convert.ToInt32(textBox6.Text)*10);
Point[] u = { x, xx, xxx };
y = pictureBox1.CreateGraphics();
y.DrawPolygon(yy, u);
Is there any way to round the corners on this? I read about it on google and it seems there's only a way to round rectangles, but not triangles.
Is there any command to do that for me or I have to do it manually?
Thanks for replies :)
Upvotes: 1
Views: 3708
Reputation: 347
public GraphicsPath DrawRoundedTriangle(RectangleF Rect, PointF point_A, PointF point_B, PointF point_C, float Radius)
{
Radius = (Rect.Height / 9f) * (Radius * 0.2f);
float Diameter = Radius * 2f;
float arcSize = (float)((Diameter / 2f) * Math.Sqrt(3.0));
GraphicsPath path = new GraphicsPath();
float sweep_angle = 120f; //Angle of Arc in the corners
if (Radius == 0f)
{
//Drawing of triangle without a rounded corner
path.AddLine(point_A, point_B);
path.AddLine(point_B, point_C);
path.AddLine(point_C, point_A);
}
else
{
PointF[] array = new PointF[6];
array[0] = new PointF(point_A.X + Radius, point_A.Y - arcSize); //Left Vertex point
array[1] = new PointF(point_B.X - Radius, point_B.Y + arcSize); //Top Vertex point
array[2] = new PointF(point_B.X + Radius, point_B.Y + arcSize); //Top Vertex point
array[3] = new PointF(point_C.X - Radius, point_C.Y - arcSize); //Right Vertex point
array[4] = new PointF(point_C.X - arcSize, point_C.Y); //Right Vertex point
array[5] = new PointF(point_A.X + arcSize, point_C.Y); //Left Vertex point
//Path Creation for Drawing
path.AddArc( (array[5].X - Radius), (array[5].Y - Diameter), Diameter, Diameter, 90f, sweep_angle); //Left Vertex
path.AddLine(array[0], array[1]); //Left Side Line
path.AddArc(array[1].X, ((array[1].Y - arcSize) + Radius), Diameter, Diameter, 210f, sweep_angle); //Top Vertex
path.AddLine(array[2], array[3]); //Right Side Line
path.AddArc((array[3].X - arcSize), (array[3].Y - (Diameter - arcSize)), Diameter, Diameter, 330f, sweep_angle); //Right Vertex
path.AddLine(array[4], array[5]); //Bottom Line
}
path.CloseFigure();
return path;
}
Upvotes: 0
Reputation: 51
I fought with the math for a bit, then I had an idea...overlaid shapes.
<Canvas >
<Polyline Margin="-1 0 0 0"
Fill="{StaticResource Yellow}"
Points="3,14.5 17,14.5 10,2 3,14.5"
StrokeStartLineCap="Round" StrokeEndLineCap="Round" StrokeLineJoin="Round"
Stroke="Black"
StrokeThickness="4"/>
<Polyline Margin="-1 0 0 0"
Fill="{StaticResource Yellow}"
Stroke="{StaticResource Yellow}"
Points="3,14.5 17,14.5 10,2 3,14.5"
StrokeStartLineCap="Round" StrokeEndLineCap="Round" StrokeLineJoin="Round"
StrokeThickness="3"/>
</Canvas>
Upvotes: 0
Reputation: 54433
It is not possible out of the box.
You can create rounded polygons like this:
GraphicsPath
which consists of these lines and in between each pair of lines a curve that connects those new endpointsFor a Triangle ABC this would mean to
Here is a piece of code that uses this method:
A GraphicsPaths to be used in the Paint event:
GraphicsPath GP = null;
A test method with a list of points, making up a triangle - (*) we overdraw by two points to make things easier; one could add the final lines and curves by ading a few lines of code instead..
private void TestButton_Click(object sender, EventArgs e)
{
Point A = new Point(5, 50);
Point B = new Point(250, 100);
Point C = new Point(50, 250);
List<Point> points = new List<Point>();
points.Add(A);
points.Add(B);
points.Add(C);
points.Add(A); // *
points.Add(B); // *
GP = roundedPolygon(points.ToArray(), 20);
panel1.Invalidate();
}
private void panel1_Paint(object sender, PaintEventArgs e)
{
if (GP == null) return;
using (Pen pen = new Pen(Brushes.BlueViolet, 3f))
e.Graphics.DrawPath(pen, GP);
}
GraphicsPath roundedPolygon(Point[] points, int rounding)
{
GraphicsPath GP = new GraphicsPath();
List<Line> lines = new List<Line>();
for (int p = 0; p < points.Length - 1; p++)
lines.Add( shortenLine(new Line(points[p], points[p+1]), rounding) );
for (int l = 0; l < lines.Count - 1; l++)
{
GP.AddLine(lines[l].P1, lines[l].P2);
GP.AddCurve(new Point[] { lines[l].P2,
supPoint(lines[l].P2,points[l+1], lines[l+1].P1),
lines[l+1].P1 });
}
return GP;
}
// a simple structure
struct Line
{
public Point P1; public Point P2;
public Line(Point p1, Point p2){P1 = p1; P2 = p2;}
}
// routine to make a line shorter on both ends
Line shortenLine(Line line, int byPixels)
{
float len = (float)Math.Sqrt(Math.Pow(line.P1.X - line.P2.X, 2)
+ Math.Pow(line.P1.Y - line.P2.Y, 2));
float prop = (len - byPixels) / len;
Point p2 = pointBetween(line.P1, line.P2, prop);
Point p1 = pointBetween(line.P1, line.P2, 1 - prop);
return new Line(p1,p2);
}
// with a proportion of 0.5 the point sits in the middle
Point pointBetween(Point p1, Point p2, float prop)
{
return new Point((int)(p1.X + (p2.X - p1.X) * prop),
(int)(p1.Y + (p2.Y - p1.Y) * prop));
}
// a supporting point, change the second prop (**) to change the rounding shape!
Point supPoint(Point p1, Point p2, Point p0)
{
Point p12 = pointBetween(p1, p2, 0.5f);
return pointBetween(p12, p0, 0.5f); // **
}
Example:
Upvotes: 9
Reputation: 239636
I think if you adjust your coordinates appropriately and specify a Width
for your Pen
greater than 1 and set the LineJoin
property to Rounded
, you should obtain a triangle with rounded corners.
Upvotes: 6