CODEWITHSUNDEEP
phpregexpreg-replace
Pierce McGeough
Pierce McGeough

Reputation: 3086

Use PHP regex to replace content to a link

I am looking to use regex in PHP to replace instances of @[SOME TEXT](id:1) to <a href="link/$id">SOME TEXT</a>

I have been trying various regex tutorials online but cannot figure it out. This is what I have so far \@\[.*\] but it selects all from @[Mr to then end Kenneth]

$text = "This is the thing @[Mr Hugh Warner](id:1) Lorem ipsum dolor sit amet, consectetur adipisicing elit. Vitae minima mollitia, sit porro eius similique fugit quis fugiat quae perferendis excepturi nam in deserunt natus eaque magni soluta esse rem. @[Kenneth Auchenberg](contact:1) Lorem ipsum dolor sit amet, consectetur adipisicing elit. Vitae minima mollitia, sit porro eius similique fugit quis fugiat quae perferendis excepturi nam in deserunt natus eaque magni soluta esse rem. @[Kenneth](id:7)";

Upvotes: 0

Views: 80

Answers (4)

Gergo Erdosi
Gergo Erdosi

Reputation: 42048

You can use a regex like this:

/@\[([^\]]+)\]\(id:(\d+)\)/

PHP code:

$pattern = '/@\[([^\]]+)\]\(id:(\d+)\)/';
$replacement = '<a href="link/$2">$1</a>';
$text = preg_replace($pattern, $replacement, $text);

echo $text;

Upvotes: 4

Kouber Saparev
Kouber Saparev

Reputation: 8105

preg_replace('/@\[([^\]]+)\]\((\w+):(\d+)\)/', '<a href="link/$2/$3">$1</a>', $text);

Upvotes: 1

Hard Tacos
Hard Tacos

Reputation: 370

\@\[.*?\]\(.*?\)

This will save is as:

Array
(
    [0] => @[Mr Hugh Warner](id:1)
)

I used this site for help: http://www.phpliveregex.com/p/7sv

Also, This doesn't have to be lazy...this works exactly the same as above:

\@\[.*\]\(.*\)

Upvotes: 0

jeroen
jeroen

Reputation: 91734

You want lazy instead of greedy matching in the example that you tried:

\@\[.*?\]
      ^ make it lazy

Another option would be to make sure you don't match any closing blockquote:

\@\[[^\]]+\]
    ^^^^^ a character class containing any character except the ] character

Upvotes: 0

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