CODEWITHSUNDEEP
bashshelleof
Abhinav Arya
Abhinav Arya

Reputation: 235

unix shell script to check for EOF

I wish to take names of two files as command line arguments in bash shell script and then for each word (words are comma separated and the file has more than one line) in the first file I need to count its occurrence in the second file. I wrote a shell script like this

 if [ $# -ne 2 ]
 then
 echo "invalid number of arguments"
 else
 i=1
 a=$1
 b=$2
 fp=*$b
 while[ fgetc ( fp ) -ne EOF   ]
 do
 d=$( cut -d',' -f$i $a )
 echo "$d"
 grep -c -o $d $b 
 i=$(( $i + 1 ))
 done
 fi

for example file1 has words abc,def,ghi,jkl (in first line ) mno,pqr (in second line)

and file2 has words abc,abc,def

Now the output should be like abc 2 def 1 ghi 0

Upvotes: 0

Views: 6252

Answers (2)

anishsane
anishsane

Reputation: 20980

Another approach:

words=( `tr ',' ' ' < file1`) #split the file1 into words...

for word in "${words[@]}"; do  #iterate in the words
    printf "%s : " "$word"
    awk 'END{print FNR-1}' RS="$word" file2
    # split file2 with 'word' as record separator.
    # print number of lines == number of occurrences of the word..
done

Upvotes: 1

anubhava
anubhava

Reputation: 785531

To read a file word by word separated by comma use this snippet:

while read -r p; do
    IFS=, && for w in $p; do
       printf "%s: " "$w"
       tr , '\n' < file2 | grep -Fc "$w"
    done
done < file1

Upvotes: 2

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