CODEWITHSUNDEEP
c++classoverloading
GuitarStrum
GuitarStrum

Reputation: 723

Calling a function in an operator overload?

I have a class A,

class A{

private:
   int num;
public:
   A(int n){ num = n; };
   int getNum(){
       return num;
   }
   A operator+(const A &other){
       int newNum = num + other.getNum();
       return A(newNum);
   };
};

Why does other.getNum() give an error? I can access variables in other (other.num) perfectly fine, but it seems that I can't ever use any of other's functions.

The error I get is something along the lines of

Invalid arguments: Candidates are int getNum().

I can write int test = getNum() but not int test = other.getNum(), but I'm almost sure I'm able to call other.getNum() somehow.

Am I overlooking something?

Upvotes: 0

Views: 61

Answers (1)

user2848971
user2848971

Reputation:

Other is marked const. Therefore, only const methods can be invoked on it. Either make other non-const or make getNum a const method. In this case, making getNum const would be the way to go.

The reason you can call getNum on this is because this is not const. Making a method const effectively makes the this pointer const.

Upvotes: 5

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