Short circuit Array.forEach like calling break

Question

[1,2,3].forEach(function(el) {
    if(el === 1) break;
});

How can I do this using the new forEach method in JavaScript? I've tried return;, return false; and break. break crashes and return does nothing but continue iteration.

Answer 1

const arr = [1, 2, 3, 4, 5, 6, 7]; // not modified

[...arr].forEach((num, i, currentArr) => {
    if (num === 4) {
        return currentArr.splice(i); // break
    }

    console.log(num);
});

Answer 2

var Book = {"Titles":[                          
    {
    "Book3" : "BULLETIN 3"
    }   
    ,
    {
    "Book1" : "BULLETIN 1"
    }
    ,
    {
    "Book2" : "BULLETIN 2"
    }    
]}

var findbystr = function(str) { 
    var return_val;
    Book.Titles.forEach(function(data){ 
        if(typeof data[str] != 'undefined')
        {
            return_val = data[str];
        } 
    }, str) 
    
    return return_val;
}

book = findbystr('Book1');
console.log(book);

Answer 3

There's no built-in ability to break in forEach. To interrupt execution you would have to throw an exception of some sort. eg.

var BreakException = {};

try {
  [1, 2, 3].forEach(function(el) {
    console.log(el);
    if (el === 2) throw BreakException;
  });
} catch (e) {
  if (e !== BreakException) throw e;
}

JavaScript exceptions aren't terribly pretty. A traditional for loop might be more appropriate if you really need to break inside it.

Use Array#some

Instead, use Array#some:

[1, 2, 3].some(function(el) {
  console.log(el);
  return el === 2;
});

This works because some returns true as soon as any of the callbacks, executed in array order, return true, short-circuiting the execution of the rest.

some, its inverse every (which will stop on a return false), and forEach are all ECMAScript Fifth Edition methods which will need to be added to the Array.prototype on browsers where they're missing.

Answer 4

The answer is, a bit counter intuitively, you don't actually have to!

There are alternative solutions that will make your code look much neater as well, a win-win situation.

By filtering the array before applying your forEach, the break/return early won't be necessary.

function isOne(num) { 
    return num === 1; 
}

function processElement(num, index) { 
    console.log(num, index);
} 

[1, 2, 3, 4, 2, 5].filter(isOne)
                  .forEach(processElement); 

If necessary, you can map your elements to add on some additional information:

function doPreCalculation(num) { 
    return num / 2;
}

[1, 2, 3, 4, 2, 5].map(doPreCalculation)
                  .filter(isOne)
                  .forEach(processElement); 

You can use these methods on Iterators aswell. Collections like NodeList can be turned into an Iterator with NodeList.values().

Answer 5

Consider to use jquery's each method, since it allows to return false inside callback function:

$.each([{user: "barney", active: false}, {user: "fred", active: false}],function(e, i) { 
   if (i % 2) return false;
   console.log(e)
})

Lodash libraries also provides takeWhile method that can be chained with map/reduce/fold etc:

var users = [
  { 'user': 'barney',  'active': false },
  { 'user': 'fred',    'active': false },
  { 'user': 'pebbles', 'active': true }
];
 
_.takeWhile(users, function(o) { return !o.active; });
// => objects for ['barney', 'fred']
 
// The `_.matches` iteratee shorthand.
_.takeWhile(users, { 'user': 'barney', 'active': false });
// => objects for ['barney']
 
// The `_.matchesProperty` iteratee shorthand.
_.takeWhile(users, ['active', false]);
// => objects for ['barney', 'fred']
 
// The `_.property` iteratee shorthand.
_.takeWhile(users, 'active');
// => []

Answer 6

There is now an even better way to do this in ECMAScript2015 (aka ES6) using the new for of loop. For example, this code does not print the array elements after the number 5:

const arr = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10];
for (const el of arr) {
  console.log(el);
  if (el === 5) {
    break;
  }
}

From the docs:

Both for...in and for...of statements iterate over something. The main difference between them is in what they iterate over. The for...in statement iterates over the enumerable properties of an object, in original insertion order. The for...of statement iterates over data that iterable object defines to be iterated over.

Need the index in the iteration? You can use Array.entries():

for (const [index, el] of arr.entries()) {
  if ( index === 5 ) break;
}

Answer 7

Breaking out of built-in Array.prototype.map function esp in React

The key thing to note here is the use of statement return to BREAK

let isBroken = false;

colours.map(item => {
    if (isBroken) {
        return;
    }
    if (item.startsWith("y")) {
        console.log("The yessiest colour!");
        isBroken = true;
        return;
    }
});

More information here: https://www.codegrepper.com/code-examples/javascript/break+out+of+map+javascript

Answer 8

I use return false and it works for me.

Answer 9

Yet another approach:

var wageType = types.filter(function(element){
  if(e.params.data.text == element.name){
    return element;
  }
});
console.dir(wageType);

Answer 10

Why don't you try wrapping the function in a Promise?

The only reason I bring it up is that I am using a function in an API that acts in a similar manner to forEach. I don't want it to keep iterating once it finds a value, and I need to return something so I am simply going to resolve a Promise and do it that way.

traverseTree(doc): Promise<any> {
  return new Promise<any>((resolve, reject) => {
    this.gridOptions.api.forEachNode((node, index) => {
    //the above function is the one I want to short circuit.
      if(node.data.id === doc.id) {
        return resolve(node);
      }
    });
  });
}

Then all you need to do is do something with the result like

this.traverseTree(doc).then((result) => {
   this.doSomething(result);
});

My above example is in typescript, simply ignore the types. The logic should hopefully help you "break" out of your loop.

Answer 11

You can use every method:

[1,2,3].every(function(el) {
    return !(el === 1);
});

ES6

[1,2,3].every( el => el !== 1 )

for old browser support use:

if (!Array.prototype.every)
{
  Array.prototype.every = function(fun /*, thisp*/)
  {
    var len = this.length;
    if (typeof fun != "function")
      throw new TypeError();

    var thisp = arguments[1];
    for (var i = 0; i < len; i++)
    {
      if (i in this &&
          !fun.call(thisp, this[i], i, this))
        return false;
    }

    return true;
  };
}

more details here.

Answer 12

You can create a variant of forEach that allows for break, continue, return, and even async/await: (example written in TypeScript)

export type LoopControlOp = "break" | "continue" | ["return", any];
export type LoopFunc<T> = (value: T, index: number, array: T[])=>LoopControlOp;

Array.prototype.ForEach = function ForEach<T>(this: T[], func: LoopFunc<T>) {
    for (let i = 0; i < this.length; i++) {
        const controlOp = func(this[i], i, this);
        if (controlOp == "break") break;
        if (controlOp == "continue") continue;
        if (controlOp instanceof Array) return controlOp[1];
    }
};

// this variant lets you use async/await in the loop-func, with the loop "awaiting" for each entry
Array.prototype.ForEachAsync = async function ForEachAsync<T>(this: T[], func: LoopFunc<T>) {
    for (let i = 0; i < this.length; i++) {
        const controlOp = await func(this[i], i, this);
        if (controlOp == "break") break;
        if (controlOp == "continue") continue;
        if (controlOp instanceof Array) return controlOp[1];
    }
};

Usage:

function GetCoffee() {
    const cancelReason = peopleOnStreet.ForEach((person, index)=> {
        if (index == 0) return "continue";
        if (person.type == "friend") return "break";
        if (person.type == "boss") return ["return", "nevermind"];
    });
    if (cancelReason) console.log("Coffee canceled because: " + cancelReason);
}

Answer 13

Another concept I came up with:

function forEach(array, cb) {
  var shouldBreak;
  function _break() { shouldBreak = true; }
  for (var i = 0, bound = array.length; i < bound; ++i) {
    if (shouldBreak) { break; }
    cb(array[i], i, array, _break);
  }
}

// Usage

forEach(['a','b','c','d','e','f'], function (char, i, array, _break) {
  console.log(i, char);
  if (i === 2) { _break(); }
});

Answer 14

try with "find" :

var myCategories = [
 {category: "start", name: "Start", color: "#AC193D"},
 {category: "action", name: "Action", color: "#8C0095"},
 {category: "exit", name: "Exit", color: "#008A00"}
];

function findCategory(category) {
  return myCategories.find(function(element) {
    return element.category === category;
  });
}

console.log(findCategory("start"));
// output: { category: "start", name: "Start", color: "#AC193D" }

Answer 15

If you need to break based on the value of elements that are already in your array as in your case (i.e. if break condition does not depend on run-time variable that may change after array is assigned its element values) you could also use combination of slice() and indexOf() as follows.

If you need to break when forEach reaches 'Apple' you can use

var fruits = ["Banana", "Orange", "Lemon", "Apple", "Mango"];
var fruitsToLoop = fruits.slice(0, fruits.indexOf("Apple"));
// fruitsToLoop = Banana,Orange,Lemon

fruitsToLoop.forEach(function(el) {
    // no need to break
});

As stated in W3Schools.com the slice() method returns the selected elements in an array, as a new array object. The original array will not be changed.

See it in JSFiddle

Hope it helps someone.

Answer 16

Quoting from the MDN documentation of Array.prototype.forEach():

There is no way to stop or break a forEach() loop other than by throwing an exception. If you need such behaviour, the .forEach() method is the wrong tool, use a plain loop instead. If you are testing the array elements for a predicate and need a boolean return value, you can use every() or some() instead.

For your code (in the question), as suggested by @bobince, use Array.prototype.some() instead. It suits very well to your usecase.

Array.prototype.some() executes the callback function once for each element present in the array until it finds one where callback returns a truthy value (a value that becomes true when converted to a Boolean). If such an element is found, some() immediately returns true. Otherwise, some() returns false. callback is invoked only for indexes of the array which have assigned values; it is not invoked for indexes which have been deleted or which have never been assigned values.

Answer 17

As mentioned before, you can't break .forEach().

Here's a slightly more modern way of doing a foreach with ES6 Iterators. Allows you to get direct access to index/value when iterating.

const array = ['one', 'two', 'three'];

for (const [index, val] of array.entries()) {
  console.log('item:', { index, val });
  if (index === 1) {
    console.log('break!');
    break;
  }
}

Output:

item: { index: 0, val: 'one' }
item: { index: 1, val: 'two' }
break!

Links

• Array.prototype.entries()
• Iterators and generators
• Destructuring assignment

Answer 18

Unfortunately in this case it will be much better if you don't use forEach. Instead use a regular for loop and it will now work exactly as you would expect.

var array = [1, 2, 3];
for (var i = 0; i < array.length; i++) {
  if (array[i] === 1){
    break;
  }
}

Answer 19

This is a for loop, but maintains the object reference in the loop just like a forEach() but you can break out.

var arr = [1,2,3];
for (var i = 0, el; el = arr[i]; i++) {
    if(el === 1) break;
}

Answer 20

I know it not right way. It is not break the loop. It is a Jugad

let result = true;
[1, 2, 3].forEach(function(el) {
    if(result){
      console.log(el);
      if (el === 2){
        result = false;
      }
    }
});

Answer 21

From your code example, it looks like Array.prototype.find is what you are looking for: Array.prototype.find() and Array.prototype.findIndex()

[1, 2, 3].find(function(el) {
    return el === 2;
}); // returns 2

Answer 22

you can follow the code below which works for me:

 var     loopStop = false;
YOUR_ARRAY.forEach(function loop(){
    if(loopStop){ return; }
    if(condition){ loopStop = true; }
});

Answer 23

This isn't the most efficient, since you still cycle all the elements, but I thought it might be worth considering the very simple:

let keepGoing = true;
things.forEach( (thing) => {
  if (noMore) keepGoing = false;
  if (keepGoing) {
     // do things with thing
  }
});

Answer 24

If you want to keep your forEach syntax, this is a way to keep it efficient (although not as good as a regular for loop). Check immediately for a variable that knows if you want to break out of the loop.

This example uses a anonymous function for creating a function scope around the forEach which you need to store the done information.

(function(){
    var element = document.getElementById('printed-result');
    var done = false;
    [1,2,3,4].forEach(function(item){
        if(done){ return; }
        var text = document.createTextNode(item);
        element.appendChild(text);
        if (item === 2){
          done = true;
          return;
        }
    });
})();

<div id="printed-result"></div>

My two cents.

Answer 25

Agree with @bobince, upvoted.

Also, FYI:

Prototype.js has something for this purpose:

<script type="text/javascript">
  $$('a').each(function(el, idx) {
    if ( /* break condition */ ) throw $break;
    // do something
  });
</script>

$break will be catched and handled by Prototype.js internally, breaking the "each" cycle but not generating external errors.

See Prototype.JS API for details.

jQuery also has a way, just return false in the handler to break the loop early:

<script type="text/javascript">
  jQuery('a').each( function(idx) {
    if ( /* break condition */ ) return false;
    // do something

  });
</script>

See jQuery API for details.

Answer 26

Use the array.prototype.every function, which provide you the utility to break the looping. See example here Javascript documentation on Mozilla developer network

Answer 27

If you don't need to access your array after iteration you can bail out by setting the array's length to 0. If you do still need it after your iteration you could clone it using slice..

[1,3,4,5,6,7,8,244,3,5,2].forEach(function (item, index, arr) {
  if (index === 3) arr.length = 0;
});

Or with a clone:

var x = [1,3,4,5,6,7,8,244,3,5,2];

x.slice().forEach(function (item, index, arr) {
  if (index === 3) arr.length = 0;
});

Which is a far better solution then throwing random errors in your code.

Answer 28

I use nullhack for that purpose, it tries to access property of null, which is an error:

try {
  [1,2,3,4,5]
  .forEach(
    function ( val, idx, arr ) {
      if ( val == 3 ) null.NULLBREAK;
    }
  );
} catch (e) {
  // e <=> TypeError: null has no properties
}
//

Answer 29

Short answer: use for...break for this or change your code to avoid breaking of forEach. Do not use .some() or .every() to emulate for...break. Rewrite your code to avoid for...break loop, or use for...break. Every time you use these methods as for...break alternative God kills kitten.

Long answer:

.some() and .every() both return boolean value, .some() returns true if there any element for which passed function returns true, every returns false if there any element for which passed function returns false. This is what that functions mean. Using functions for what they doesn't mean is much worse then using tables for layout instead of CSS, because it frustrates everybody who reads your code.

Also, the only possible way to use these methods as for...break alternative is to make side-effects (change some vars outside of .some() callback function), and this is not much different from for...break.

So, using .some() or .every() as for...break loop alternative isn't free of side effects, this isn't much cleaner then for...break, this is frustrating, so this isn't better.

You can always rewrite your code so that there will be no need in for...break. You can filter array using .filter(), you can split array using .slice() and so on, then use .forEach() or .map() for that part of array.

Answer 30

This is just something I came up with to solve the problem... I'm pretty sure it fixes the problem that the original asker had:

Array.prototype.each = function(callback){
    if(!callback) return false;
    for(var i=0; i<this.length; i++){
        if(callback(this[i], i) == false) break;
    }
};

And then you would call it by using:

var myarray = [1,2,3];
myarray.each(function(item, index){
    // do something with the item
    // if(item != somecondition) return false; 
});

Returning false inside the callback function will cause a break. Let me know if that doesn't actually work.