CODEWITHSUNDEEP
dart
CarrKnight
CarrKnight

Reputation: 2918

In Dart is there a quick way to convert int to double?

Very simple issue. I have the useless class:

class Useless{
  double field;
  Useless(this.field);
}

I then commit the mortal sin and call new Useless(0); In checked mode (which is how I run my tests) that blows up, because 'int' is not a subtype of type 'double'.

Now, it works if I use new Useless(0.0) , but honestly I spend a lot of time correcting my tests putting .0s everywhere and I feel pretty dumb doing that.

As a temporary measure I rewrote the constructor as:

    class Useless{
      double field;
      Useless(num input){
          field = input.toDouble();
      }
    }

But that's ugly and I am afraid slow if called often. Is there a better way to do this?

Upvotes: 158

Views: 191615

Answers (9)

jordan wilfry
jordan wilfry

Reputation: 33

This is how you can cast from int to double int a = 2; double b = a*1.0;

Upvotes: 0

jamesdlin
jamesdlin

Reputation: 89926

In Dart 2.1, integer literals may be directly used where double is expected. (See https://github.com/dart-lang/sdk/issues/34355.)

Note that this is syntactic sugar and applies only to literals. int variables still won't be automatically promoted to double, so code like:

double reciprocal(double d) => 1 / d;

int x = 42;
reciprocal(x);

would fail, and you'd need to do:

reciprocal(x.toDouble());

Upvotes: 93

Umar Calcuttawala
Umar Calcuttawala

Reputation: 331

use toDouble() method.
For e.g.:

int a = 10
print(a.toDouble) 
//or store value in a variable and then use
double convertedValue = a.toDouble()

Upvotes: 18

Michael Elimu
Michael Elimu

Reputation: 71

Since all divisions in flutter result to a double, the easiest thing I did to achieve this was just to divide the integer value with 1: i.e. int x = 15; double y = x /1;

Upvotes: 5

Ricardo
Ricardo

Reputation: 2291

I'm using a combination:

static double checkDouble(dynamic value) {
  if (value is String) {
    return double.parse(value);
  } else if (value is int) {
    return 0.0 + value;
  } else {
    return value;
  }
}

Upvotes: 3

Ronen Rabinovici
Ronen Rabinovici

Reputation: 9092

Simply toDouble()

Example:

int intVar = 5;
double doubleVar = intVar.toDouble();

Thanks to @jamesdlin who actually gave this answer in a comment to my previous answer...

Upvotes: 214

Lebohang Mbele
Lebohang Mbele

Reputation: 3748

From this attempt:

class Useless{
  double field;
  Useless(num input){
    field = input.toDouble();
  }
}

You can use the parse method of the double class which takes in a string.

class Useless{
  double field;
  Useless(num input){
    field = double.parse(input.toString()); //modified line
  }
}

A more compact way of writing the above class using constructor's initialisers is:

class Useless{
  double _field;
  Useless(double field):_field=double.parse(field.toString());
}

Upvotes: 8

Mattia
Mattia

Reputation: 6524

You can also use:

int x = 15;
double y = x + .0;

Upvotes: 47

Danny Tuppeny
Danny Tuppeny

Reputation: 42333

There's no better way to do this than the options you included :(

I get bitten by this lots too, for some reason I don't get any warnings in the editor and it just fails at runtime; mighty annoying :(

Upvotes: 4

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