CODEWITHSUNDEEP
c++constructor
Harshit
Harshit

Reputation: 103

What does it mean by parameterized constructor with default value?

I am learning c++. I made this program but on compiling it, the program shows ambigious error. I don't understand that if i am making an object with no arguments then it should only call default constructor & the program should run without any error. Here is the code:

#include<iostream>
using namespace std;
class room
{
 int length,width;
 public:
 room()
 {
  cout<<"Default constructor"; 
 } 
 room(int l=0)
 {
      cout<<"Constructor"; //the compiler is taking this also as default constructor
 }
 room(int l=0,int w=0)
 {
  cout<<"Constructor";  //the compiler is taking this also as default constructor on making other two as comment
 }
};
int main()
{
 room r1;
 return 0;
}

I have tried this code on compiler like Codeblocks, Dev c++ & GCC also.

Upvotes: 0

Views: 491

Answers (2)

P0W
P0W

Reputation: 47824

room r1 is ambiguous because a constructor with all parameters defaulted is already available as room() as a default constructor

§ 12.1

A default constructor for a class X is a constructor of class X that can be called without an argument. If there is no user-declared constructor for class X, a constructor having no parameters is implicitly declared as defaulted (8.4).

Upvotes: 3

Sayu Sekhar
Sayu Sekhar

Reputation: 169

You have 3 constructors which could be called without supplying any arguments. So the compiler gets confused by these 3 constructors.

Upvotes: 0

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