Reputation: 873
I load a file f
with the numpy.loadtxt
function and wanted to extract some dates.
The date has a format like this: 15.08. - 21.08.2011
numpyarr = loadtxt(f, dtype=str, delimiter=";", skiprows = 1)
alldate = numpyarr[:,0][0]
dat = datetime.datetime.strptime(alldate,"%d.%m. - %d.%m.%Y")
And here is the whole error:
Traceback (most recent call last):
File "C:\PYTHON\Test DATETIME_2.py", line 52, in <module>
dat = datetime.datetime.strptime(alldate,"%d.%m. - %d.%m.%Y")
File "C:\Python27\lib\_strptime.py", line 308, in _strptime
format_regex = _TimeRE_cache.compile(format)
File "C:\Python27\lib\_strptime.py", line 265, in compile
return re_compile(self.pattern(format), IGNORECASE)
File "C:\Python27\lib\re.py", line 190, in compile
return _compile(pattern, flags)
File "C:\Python27\lib\re.py", line 242, in _compile
raise error, v # invalid expression
sre_constants.error: redefinition of group name 'd' as group 3; was group 1
Does somebody have an idea was going on?
Upvotes: 1
Views: 401
Reputation: 11734
A datetime
holds a single date & time, while your field contains two dates and trys to extract them into a single variable. Specifically, the error you're getting is because you've used %d
and %m
twice.
You can try something along the lines of:
a = datetime.datetime.strptime(alldate.split('-')[0],"%d.%m. ")
b = datetime.datetime.strptime(alldate.split('-')[1]," %d.%m.%Y")
a = datetime.datetime(b.year, a.month, a.day)
(it's not the best code, but it demonstrates the fact that there are two dates in two different formats hiding in your string).
Upvotes: 1