Reputation: 2103
I'm using this code to zip a folder
D:\VIRTUAL\consuladoperurio.com.br\WWW\siscons\test\wordtemplatedownload\pasta
into test.zip. The folder "pasta" has the follow tree
pasta
subfolder
styles.xml
When I run the code
$wordtemplatedownloadpath ="D:\\VIRTUAL\\consuladoperurio.com.br\\WWW\\siscons\\test\\wordtemplatedownload\\"
Zip($wordtemplatedownloadpath."pasta", $wordtemplatedownloadpath."test.zip");
and then extract test.zip I get the folder and file
respectively. When I need the first tree.
I'm trying to replace '/' to '\' but don't work. How I will be able to solve that?
Upvotes: 1
Views: 79
Reputation: 1872
I will concentrate on your last question "I'm trying to replace '/' to '\' but don't work. How I will be able to solve that?" as at the moment it is unclear what you are asking about.
But if you are having problems specifying a path to your directory try to use the constant DIRECTORY_SEPARATOR within your path definition
Example
$wordtemplatedownloadpath ="D:" . DIRECTORY_SEPARATOR . "VIRTUAL" . DIRECTORY_SEPARATOR . "consuladoperurio.com.br" . DIRECTORY_SEPARATOR . "WWW" . DIRECTORY_SEPARATOR . "siscons" . DIRECTORY_SEPARATOR . "test" . DIRECTORY_SEPARATOR . "wordtemplatedownload" . DIRECTORY_SEPARATOR ;
Please let me know if this fixes your problem
Upvotes: 1