CODEWITHSUNDEEP
stringmatlabmatrix
Rash
Rash

Reputation: 4336

Evaluating string cells in MATLAB

I have,

labels = {'A' , 'B' , 'C'};

results =
           A
           A
           C
           .
           .
           B

result is a 1000*1 char,

I want compare the the labels with results and get a logical array.

I finally found that,

n = cellstr(results);
m = 'A';
strcmp(n,m)

works, but I want to do it in a loop, so I cant have m = 'A';, it should be m = labels(1);, which won't work.

Upvotes: 2

Views: 55

Answers (2)

chappjc
chappjc

Reputation: 30579

Use ismember like this (v is like cellstr(result) in your case):

>> labels = {'A' , 'B' , 'C'};
>> v = cellstr(char(randi(15,20,1)+64)).' %' uni. random sample of letters from A to O

v = 

  Columns 1 through 10

    'M'    'D'    'I'    'J'    'A'    'J'    'F'    'A'    'H'    'C'

  Columns 11 through 20

    'B'    'D'    'C'    'C'    'A'    'J'    'E'    'I'    'K'    'H'

>> [lia,locb] = ismember(v,labels)

lia =

  Columns 1 through 12

     0     0     0     0     1     0     0     1     0     1     1     0

  Columns 13 through 20

     1     1     1     0     0     0     0     0


locb =

  Columns 1 through 12

     0     0     0     0     1     0     0     1     0     3     2     0

  Columns 13 through 20

     3     3     1     0     0     0     0     0

This might help clarify the outputs:

>> v(lia)

ans = 

    'A'    'A'    'C'    'B'    'C'    'C'    'A'

>> labels(locb(lia))

ans = 

    'A'    'A'    'C'    'B'    'C'    'C'    'A'

In other works, find(lia) are the indexes in v of the characters that also exist in labels, and locb(lia) gives the index into labels for those elements.

Upvotes: 2

lakshmen
lakshmen

Reputation: 29064

Try something like this:

n = cellstr(results);

for k=1:3
  m = labels(k);
  strcmp(n,m);
end

Upvotes: 0

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