CODEWITHSUNDEEP
linuxbashshell
chun
chun

Reputation: 847

How to pass parameters to a Bash script?

I have a bash script as below, and I want it to read two dates as parameters, for example: myshell date1 date2. How do I assign parameters to variables date1 and date2?

sed "s/$date1/$date2/g" wlacd_stat.xml >tmp.xml
mv tmp.xml wlacd_stat.xml

Upvotes: 56

Views: 95764

Answers (4)

Simone Margaritelli
Simone Margaritelli

Reputation: 4733

$0
$1
$2

And so on will contain the script name, then the first and the second line argument.

Upvotes: 6

ghostdog74
ghostdog74

Reputation: 342363

You use $1, $2 in your script. E.g:

date1="$1"
date2="$2"
sed "s/$date1/$date2/g" wlacd_stat.xml >temp.xml
mv temp.xml wlacd_stat.xml

Upvotes: 79

Dennis Williamson
Dennis Williamson

Reputation: 360075

To iterate over the parameters, you can use this shorthand:

#!/bin/bash
for a
do
    echo $a
done

This form is the same as for a in "$@".

Upvotes: 9

mouviciel
mouviciel

Reputation: 67829

Bash arguments are named after their position.

Moreover, if you need to handle one argument after the other, you can shift them and always use $1:

while [ $# -gt 0 ]
do
    echo $1
    shift
done

Upvotes: 8

Related Questions