CODEWITHSUNDEEP
javascriptphpjqueryajax
Mani
Mani

Reputation: 37

delete data with ajax

i am unable to delete records from database, fetching code is working but delete code is not working. please help me out.. thanks in advance

code to fetch data with ajax

    $(document).ready(function(){
        done();
    });
    function done(){
        setTimeout(function(){
            updates();
            done();
            }, 200);
    }

    function updates(){
        $.getJSON("fetch.php",function(data){
            $("table").empty();
            $("table").append("<tr><td>Name</td><td>Date</td><td>Delete</td></tr>");
            $.each(data.result, function(){
                $("table").append("<tr><td>"+this['text']+"</td><td>"+this['date']+"</td><td><a id='del' href='"+this['id']+"'>Del</a></td></tr>");
            });
        });
    }

code to delete data with ajax

        $(function() {
    $("#del").click(function(){
    var element = $(this);
    var id = element.attr("id");
    var dataString = 'id=' + id;
    if(confirm("Sure you want to delete this comment?"))
    {
       $.ajax({
       type: "GET",
       url: "del.php",
       data: dataString,
       success: function(){

            }
         });
    }
    return false;
    });

});

php code del.php

$last_page_id = $_REQUEST['d_i_d'];
$sql = mysql_query("delete from time where id = '{$last_page_id}'");

if(!$sql){
    echo mysql_error();
}else{
    header('location: index.php');
}

Upvotes: 0

Views: 235

Answers (2)

rgwsk65
rgwsk65

Reputation: 309

Try to pass data like this:

$.ajax{
    url: 'del.php',
    method: 'GET',
    data: {
        id: // Put your ID value here
    }
    success: function(){
        // Put your success code here
    }
}

Look that fragment:

$("#del").click(function(){
var element = $(this);
var id = element.attr("id");
...

id variable will always hold "del" value, because you get ID attr of $('#del').

Upvotes: 0

nvanesch
nvanesch

Reputation: 2600

Ajax data: dataString = 'id=' + id;

calling it in php: $last_page_id = $_REQUEST['d_i_d'];

You can get the id with $_REQUEST['id']

Please note that mysql_ is deprecated: Why shouldn't I use mysql_* functions in PHP?

And that your code is open to SQL injection: http://en.wikipedia.org/wiki/SQL_injection

Upvotes: 1

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