Reputation: 13178
I'm trying to create init
functions in Swift
and create instances from Objective-C
. The problem is that I don't see it in Project-Swift.h
file and I'm not able to find the function while initializing. I have a function defined as below:
public init(userId: Int!) {
self.init(style: UITableViewStyle.Plain)
self.userId = userId
}
I even tried putting @objc(initWithUserId:)
and I keep getting the same error again. Is there anything else I'm missing? How do I get the constructor visible to Objective-C
code?
I read the below for this:
How to write Init method in Swift
How to define optional methods in Swift protocol?
Upvotes: 34
Views: 20075
Reputation: 300
use this one:
var index: NSInteger!
@objc convenience init(index: NSInteger) {
self.init()
self.index = index
}
Upvotes: 11
Reputation: 93276
The issue you're seeing is that Swift can't bridge optional value types -- Int
is a value type, so Int!
can't be bridged. Optional reference types (i.e., any class) bridge correctly, since they can always be nil
in Objective-C. Your two options are to make the parameter non-optional, in which case it would be bridged to ObjC as an int
or NSInteger
:
// Swift
public init(userId: Int) {
self.init(style: UITableViewStyle.Plain)
self.userId = userId
}
// ObjC
MyClass *instance = [[MyClass alloc] initWithUserId: 10];
Or use an optional NSNumber?
, since that can be bridged as an optional value:
// Swift
public init(userId: NSNumber?) {
self.init(style: UITableViewStyle.Plain)
self.userId = userId?.integerValue
}
// ObjC
MyClass *instance = [[MyClass alloc] initWithUserId: @10]; // note the @-literal
Note, however, you're not actually treating the parameter like an optional - unless self.userId
is also an optional you're setting yourself up for potential runtime crashes this way.
Upvotes: 41