CODEWITHSUNDEEP
pythoncopy
TsvGis
TsvGis

Reputation: 632

Python shutil.copytree() is there away to track the status of the copying

I have a lot of raster files (600+) in directories that I need copy into a new location (including their directory structure). Is there a way to track the status of the copying using shutil.copytree()? Normally with files I would use the code below, but not sure how to do the same with shutil.copytree():

for currentFolder, subFolder, fileNames in os.walk(sourceFolder):
   for i in fileNames:
        if i.endswith(".img"):
            print "copying {}".format(i)
            shutil.copy(os.path.join(currentFolder,i), outPutFolder)

Upvotes: 7

Views: 11419

Answers (3)

nbeuchat
nbeuchat

Reputation: 7091

Another option is to use the copy_function argument of copytree. The advantage is that it will be called for every file that is copied instead of each folder. 

from shutil import copytree,copy2

def copy2_verbose(src, dst):
    print('Copying {0}'.format(src))
    copy2(src,dst)

copytree(source, destination, copy_function=copy2_verbose)

Upvotes: 12

Vorticity
Vorticity

Reputation: 4928

Python 2.7

The source code for shutil from Python 2.7 can be found here. You should be able to copy the source code, then add print name to line 282.

Python 3.4

The source code for shutil from Python 3.4 can be found here. You should be able to copy the source code, then add print name to line 307.

Upvotes: 3

user3885927
user3885927

Reputation: 3503

Yes, something like this is possible by taking advantage of the function name passed in for 'ignore' parameter. In fact something like this is given in the example section of python docs: https://docs.python.org/2/library/shutil.html#copytree-example

Example pasted below as well:

from shutil import copytree
import logging

def _logpath(path, names):
    logging.info('Working in %s' % path)
    return []   # nothing will be ignored

copytree(source, destination, ignore=_logpath)

Upvotes: 16

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