Reputation: 18660
I'm trying to toggle all checkboxes on a table and my code works but has a few issues and I don't find how to get ride of them. So here is the code:
$(function () {
$('#toggleCheckbox').on('click', function () {
var $toggle = $(this).is(':checked');
$("#codigoArancelarioBody").find("input:checkbox").click();
});
});
Take a look at this Fiddle I setup for testing and do this tests:
#codigoArancelarioBody
get checked and this is rightHow I can fix this? Also I'll like to add a class 'removedAlert' to those TR I mark, how?
Upvotes: 0
Views: 61
Reputation: 20471
You need two click event handlers, one for the check/uncheck all box and one for the other ones
JS
$('#toggleCheckbox').on('click', function () {
var $toggle = $(this).is(':checked');
$("#codigoArancelarioBody").find("input:checkbox").prop("checked", $toggle);
});
$("#codigoArancelarioBody input:checkbox").on('click', function () {
if (!$(this).is(':checked')) {
$('#toggleCheckbox').prop("checked", false);
} else if ($("#codigoArancelarioBody input:checkbox").length == $("#codigoArancelarioBody input:checkbox:checked").length) {
$('#toggleCheckbox').prop("checked", true);
}
});
since the same code will be applied in a lot of places on my code and to avoid DRY, I'll like to pass the selector as a parameter in all your code solution could you edit your post to achieve this?
$toggleCheckBox = $('#toggleCheckbox');
$checkBoxTbody = $("#codigoArancelarioBody");
$toggleCheckBox.on('click', function () {
var $toggle = $(this).is(':checked');
$checkBoxTbody.find("input:checkbox").prop("checked", $toggle);
});
$checkBoxTbody.find("input:checkbox").on('click', function () {
if (!$(this).is(':checked')) {
$toggleCheckBox.prop("checked", false);
} else if ($checkBoxTbody.find("input:checkbox").length == $checkBoxTbody.find("input:checkbox:checked").length) {
$toggleCheckBox.prop("checked", true);
}
});
Upvotes: 1
Reputation: 25772
The code is actually executing what you told it to do, i.e. every time I click the checkbox on top click to other checkboxes. This way if a box is checked it will uncheck itself, because it won't mind if the top is checked or not.
What you really want is "when I check the box on top, check all the others, when I uncheck it, then uncheck all the others", which is sort of different as you see.
Try this:
$(function () {
// best practice: always store the selectors you access multiple times
var checkboxes = $("#codigoArancelarioBody").find("input:checkbox"),
toggleAll = $('#toggleCheckbox');
toggleAll.on('click', function () {
// is the top checkbox checked? return true, is it unchecked? Then return false.
var $toggle = $(this).is(':checked');
// .prop('checked', true) makes it checked, .prop('checked', false) makes it unchecked
checkboxes.prop('checked', $toggle);
});
});
see: http://jsfiddle.net/gleezer/nnfg80x1/3/
Upvotes: 0
Reputation: 3939
If you don't need the "click" event for something else you can do this:
$(function () {
$('#toggleCheckbox').on('change', function () {
var toggle = $(this).is(':checked');
$("#codigoArancelarioBody").find("input:checkbox").prop('checked', toggle ).closest('tr').addClass('removedAlert');
});
});
Upvotes: 0