CODEWITHSUNDEEP
bashvariablesstring-interpolation
capser
capser

Reputation: 2635

bash variable interpolation separate variables by a hyphen or underscore

This is a simple script just to see if the file has been downloaded. On this script the find command always evaluated to zero - even if it didn't find anything. So I commented it out.

on the filename="day_CTRwFEES_hoo01M_" I had to add an underscore to the end of the filename.

Using an underscore $filename_$yesterday.CSV to separate the two did not work. - I had to take out the underscore, add it to the filename and then combine the variables to make it work like this - $filename$yesterday.

How could I get it to work without adding the underscore to the end of the variable $filename? 

#!/bin/bash
set -x
dayofweek=$(/bin/date +%w)
today=$(/bin/date +%Y%m%d)
yesterday=$(/bin/date -d "1 day ago" +%Y%m%d)
friday_morning=$(/bin/date -d "3 days ago" +%Y%m%d)
filename="day_CTRwFEES_hoo01M_"

#if find /data/today/ -type f -name "$filename_$yesterday.CSV" ; then
if ls "/data/today/$filename$yesterday.CSV" ; then
    echo "successful"
else
    echo "$filename$yesterday.CSV was not downloaded, please check." | mail -s "$filename$yesterday.CSV not downloaded" casper@big_bank.com
    fi

casper@good_host5981dap:~/walt/morning_checks$ ./check_day_CTRwFEES_hoo01M
++ /bin/date +%w
+ dayofweek=5
++ /bin/date +%Y%m%d
+ today=20141024
++ /bin/date -d '1 day ago' +%Y%m%d
+ yesterday=20141023
++ /bin/date -d '3 days ago' +%Y%m%d
+ friday_morning=20141021
+ filename=day_CTRwFEES_hoo01M_
+ ls data/today/day_CTRwFEES_hoo01M_20141023.CSV
/data/today/day_CTRwFEES_hoo01M_20141023.CSV
+ echo successful
successful

~

Upvotes: 4

Views: 3773

Answers (3)

gniourf_gniourf
gniourf_gniourf

Reputation: 46823

Several possibilities:

  • The most natural one: enclose your variable name in curly brackets (Ignacio Vazquez-Abrams's solution):

    echo "${filename}_$yesterday.CSV"

  • Since your separator is a rather special character, you may use a backslash (Sriharsha's Kallury's solution):

    echo "$filename\_$yesterday.CSV"

  • (Ab)use quotes:

    echo "$filename""_$yesterday.CSV"

    or

    echo "$filename"_"$yesterday.CSV"

  • Use an auxiliary variable for the separator:

    sep=_
echo "$filename$sep$yesterday.CSV"

  • Use an auxiliary variable for the final string, and build it step by step:

    final=$filename
final+=_$yesterday.CSV
echo "$final"

    or in a longer fashion:

    final=$filename
final+=_
final+=$yesterday
final+=.CSV
echo "$final"

  • Use an auxiliary variable for the final string, and build it with printf:

    printf -v final "%s_%s.CSV" "$filename" "$yesterday"
echo "$final"

(feel free to add other methods to this post).

Upvotes: 3

Sriharsha Kalluru
Sriharsha Kalluru

Reputation: 1823

You can use backslash to do that.

# filename=test
# yesterday=somedate
# echo $filename_$yesterday.csv
somedate.csv
# echo $filename\_$yesterday.csv
test_somedate.csv
#

Upvotes: 0

Ignacio Vazquez-Abrams
Ignacio Vazquez-Abrams

Reputation: 798556

By telling bash where the variable name ends.

"${filename}_$yesterday.CSV"

Upvotes: 11

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