Reputation: 1433
I'm trying to figure out if there's a way to use object destructuring of default parameters without worrying about the object being partially defined. Consider the following:
(function test({a, b} = {a: "foo", b: "bar"}) {
console.log(a + " " + b);
})();
When I call this with {a: "qux"}
, for instance, I see qux undefined
in the console when what I really want is qux bar
. Is there a way to achieve this without manually checking all the object's properties?
Upvotes: 133
Views: 53464
Reputation: 665574
Yes. You can use "defaults" in destructuring as well:
(function test({a = "foo", b = "bar"} = {}) {
console.log(a + " " + b);
})();
This is not restricted to function parameters, but works in every destructuring expression.
Upvotes: 264