Reputation: 690
I have a few classes. Lets say:
public class A
{
public void SomeAction()
{
Debug.Write("I was declared in class: and my name is:");
}
}
And
public class B
{
public static A myClass = new A();
}
public class C
{
public static A myClass = new A();
}
public class D
{
public static A myClass = new A();
}
What I want "SomeAction" in class A to do is to print out which class it was initialized in.
So that for example in another class I called C.myClass.SomeAction();
it would print out "I was declared in class C
my name is myClass
"
I hope this makes sense.
The reasons im doing this is for debugging within automated testing. I understand its not the best way to do things but its a requirement of the business.
Upvotes: 3
Views: 1195
Reputation: 57959
This requirement can be satisfied without inheritance or passing the object; we can get the name of the class that calls the constructor from within the body of the constructor by examining the stack.
public class A
{
private string _createdBy;
public void SomeAction()
{
Console.WriteLine("I was declared in class [{0}]", _createdBy);
}
public A()
{
var stackFrame = new StackFrame(1);
var method = stackFrame.GetMethod();
_createdBy = method.DeclaringType.Name;
}
}
In terms of performance, I am assuming that you are not creating many instances of these objects. You could also predicate this on whether you are doing a DEBUG build or on some other setting, so that this stuff is skipped entirely in your production executables.
Upvotes: 7
Reputation: 622
Since you only reference an instance of class A in your other classes, I think there is no other way then setting a reference to the type which created class A, like eddie_cat already mentioned. You could do something like this:
public class B
{
public static A myClass = new A(typeof(B));
}
And then your class A would look like:
public class A
{
// store the parent type
private Type mParentClass;
// provide parent type during construction of A
public A(Type parentClass)
{
mParentClass = parentClass;
}
// note that method cannot be static anymore, since every instance of A might
// have a different parent
public void SomeAction()
{
// access field where parent type is stored.
Debug.Write("I was declared in class: {0} and my name is:",mParentClass.Name);
}
}
Upvotes: 2
Reputation: 7147
I think you have two choices. Either set a property in A, or inherit from A. Personally, I prefer inheriting from A, because then A could just use GetType().
public class A
{
public void SomeMethod()
{
Debug.Write(string.Format("I was declared in class: {0}",this.GetType()));
}
}
public class B : A
{
}
var instanceOfB = new B();
instanceOfB.SomeMethod();
Upvotes: 1