Reputation:
I have the following arrays defined in a bash script
IFS=, read -r -a start_files <<< $(head -n 1 file.txt)
IFS=, read -r -a end_files <<< $(tail -n 1 file.txt)
I read also two values from a file
micro=1000000
IFS=#
[ ! -f $INPUT ] && { echo "$INPUT file not found"; exit 99; }
while read start_time end_time
do
start_time=$(bc <<< "scale=6; $start_time/$micro")
end_time=$(bc <<< "scale=6; $end_time/$micro")
...
done < $INPUT
IFS=$OLDIFS
The values stored in the arrays and in start_time and end_time are epoch times, I mean values like 1361810326.840284000, 1361862515.600478000, 1361990369.166456000
In the "..." line I want to compare the values of start_time and end_time with all the values stored in an array in the following way
for i in `seq 0 116`;
do
if [ $start_time -ge ${start_files[$i]} && $start_time -le ${end_files[$i]}]; then
startF=$i
fi
done
for j in `seq 0 116`;
do
if [ $end_time -ge ${start_files[$j]} && $end_time -le ${end_files[$j]}]; then
endF = $j
fi
done
However this code yields a syntax error. What am I doing wrong?
Upvotes: 0
Views: 91
Reputation: 74595
If you are using POSIX shell-style comparisons, it is good practice to put each test in its own square brackets. Also, you were missing a space from the end of the comparison. Remember that ]
is an argument to the function [
, rather than a syntactical construct:
for i in {0..116}; do
if [ "$start_time" -ge "${start_files[$i]}" ] && [ "$start_time" -le "${end_files[$i]}" ]; then
startF="$i"
fi
done
Same for the other one. I have quoted your variables as it is a good habit to get into. I have also used a brace expansion rather than calling seq
.
If you are using bash, you can take advantage of the nicer arithmetic syntax:
for ((i=0; i<=116; ++i)); do
if (( start_time >= ${start_files[$i]} && start_time <= ${end_files[$i]} )); then
startF="$i"
fi
done
Upvotes: 1