CODEWITHSUNDEEP
bashshellcommand-prompt
Heath Mitchell
Heath Mitchell

Reputation: 372

Bash: making my own shell

I am making a shell that resembles Command Prompt (it is not finished) but it doesn't work. Here it is:

#!/bin/bash
VER=$(lsb_release -sr)
OS=$(lsb_release -si)
echo "Linux [Distro $OS Version $VER]"
echo "<c> None"
echo -n "${PWD}>"
read $cmd
eval $cmd

I am running on Crunchbang. When I run it:

crunchbang@crunchbang:~$ ./cmd.sh
Linux [Distro Debian Version 7.0]
/home/crunchbang>echo "abc"    
crunchbang@crunchbang:~$

What it should be:

crunchbang@crunchbang:~$ ./cmd.sh
Linux [Distro Debian Version 7.0]
/home/crunchbang>echo "abc"
abc
crunchbang@crunchbang:~$

Even better:

crunchbang@crunchbang:~$ ./cmd.sh
Linux [Distro Crunchbang Version 11]
/home/crunchbang>echo "abc"
abc
crunchbang@crunchbang:~$

Upvotes: 0

Views: 128

Answers (2)

Tommy Jollyboat
Tommy Jollyboat

Reputation: 239

You need to take the $ off the read line

read cmd

Bash is expanding the variable to nothing, and executing "read"

Upvotes: 1

Etan Reisner
Etan Reisner

Reputation: 80931

read $cmd is incorrect. You meant read cmd.

You only use $ to reference a variable, not name one.

Your input is likely ending up in $REPLY.

Upvotes: 2

Related Questions